A black hole made of ordinary water? Years ago I read a book about black holes. It said it is theoretically possible to make a black hole from ordinary-density materials, like tap water. It would take a lot -- about the size of a galaxy IIRC. But it implies no singularity, so I guess you could be inside a black hole and things would seem normal. Can anyone confirm this?
EDIT: What I envisioned is water in the shape of a disk, rotating like a galaxy, and mass is added to it until it becomes a black hole. If you have water about 1 km thick, then at a radius of about 10^20 km the Swarzchild radius will be bigger. I'm wondering what happens at that point, viewed from the inside.
EDIT2: The example above would be about 100x the diameter of the Milky Way. So re-envision it as 100km thick and the same diameter as our galaxy. Secondly, the density of this "galaxy" is about 10^18 times that of a typical galaxy. So you would have to put the mass of a billion billion galaxies into one galaxy in order to witness the creation of a black hole from within.
 A: This is indeed possible. To "create" a black hole, you either can compress some object to its Schwarzschild radius or stack up more matter to it. When it reaches a critical size, it will become a black hole.
To see why this is the case, let's look at the formulae for Schwarzschild radius
$$r_s=\frac{2GM}{c^2}\tag1$$
and the volume of a sphere
$$M=\rho\frac43\pi r^3\implies r=\sqrt[\uproot 2\scriptstyle3]{\frac{3M}{4\rho\pi}}\tag2$$
You can see that $r_s\propto M$, but $r\propto\sqrt[\scriptstyle 3] M$. So as you increase the mass of an object (by "adding stuff" to it), the Schwarzschild radius will increase faster than its actual radius. So there will be a certain radius at which the object will be smaller than its Schwarzschild radius - it will collapse into a black hole.
However, that does mean that there will be a singularity. When that radius is reached, the object won't just stay how it is. It will collapse to a singularity.

See The Black Hole Tipping Point by minutephysics on YouTube.
A: The mass of a black hole determines the radius of the horizon. There are proportionality constants involving Newton's constant G and the speed of light c. But, in units where those are 1, it's just mass=radius.
That means the volume of an object that is just barely outside its own horizon is proportional to the cube of the radius, and thus the cube of the mass.
Vol propotional to mass cubed
Density = mass / vol proportional to 1 /mass^2
That means the density of an object just outside its horizon radius decreases as the mass increases. So by the time you get a mass the size of our galaxy, the density when it is just outside its own horizon is roughly that of air.
But this does not prevent the formation of a horizon, nor a singularity. The singularity forms when the object goes below its horizon. This is because of the fact that, inside the horizon, all timelike paths lead closer to the center of the black hole. Lower density does not prevent that, since the density will rise without limit once the object goes inside its own horizon.
