# Why no fundamental force from the Higgs? [duplicate]

I wish to ask whether I understand the following correctly. This universe seems to have six fundamental elementary bosons namely photon $(\gamma),\ W$-bosons$(W^+,W^-),$ gluon$(g),\ Z$-boson $(Z)$, Higgs boson$(H^0)$ and graviton$(G)$. Each fundamental force field of nature is mediated by the interaction of each of these particles, namely electromagnetism from $\gamma$, strong force from $g$, weak force from $Z,W^+,W^-,$ gravitation from $G$. This brings forward another question, I know that particles get there mass from interaction of $H^0$, but does it also analogously result in some fundamental force ? If not, then why the exception?

## marked as duplicate by Ben Crowell, user1504, Qmechanic♦Jun 6 '13 at 19:08

• The Higgs boson is a spin-0 field while all others have spin-1. (Graviton has spin-2) – Prahar Jun 6 '13 at 16:31
• Small suggestion: a more descriptive title would help, since as it stands this could apply to any question on the site. – user10851 Jun 6 '13 at 16:31
• Related and partial duplicate: physics.stackexchange.com/q/1080 – Alfred Centauri Jun 6 '13 at 16:34
• Edited the title to make it more descriptive. But this is a duplicate -- voting to close. – Ben Crowell Jun 6 '13 at 18:41

While all the particles you mention are bosons they don't all play the same role since they have different spin. The photon, the $W$-bosons, the $Z$-boson and the gluons are all spin-1 particles. A force mediated by a spin-1 particle can be both attractive and repulsive depending on the charges of the particles exchanging the bosons. The graviton, on the other hand, has spin 2, and the force mediated by a pin-2 boson is always attractive. This explains why electric charges can either attract or repel each other depending on the signs of the charges, but gravity always makes masses attract to each other.