Here, the following explanation for Hawking radiation in canonical quantum gravity is given:
The local energy density is well-defined as the 00 component of the stress-energy tensor. It is frame dependent but in locally strong fields it is locally large in every frame. In the quantum version, a strong gravitational field is like a strong electromagnetic field, described not by an empty vacuum state but by a state full of energy (as defined by the energy-stress tensor).
The space-time inhomogeneity due to gravitation is described by a massless tensor field called the gravitational field (or the metric, in a geometric view that doesn't survive quantization). In canonical quantum field theory, which must be used in order to describe particle production, space-time is just a smooth manifold without predefined metric. The gravitational field (i.e., the quantized metric) is now described by a massless quantum field tensor operator that gives rise in the usual way to creation and annihilation operators for gravitons.
Just as particle pair production from strong electromagnetic fields is inevitable through processes such as $2\gamma\to e^-+e^+$, where $\gamma$ denotes a photon, so particle production from strong gravitational fields is inevitable: If one looks at the S-matrix in the tree approximation of canonical quantum gravity + QED, one gets processes such as $2g\to 2\gamma$ and $2g\to e^-+e^+$, where $g$ denotes a graviton. The first process happens at any positive energy since both sides are massless; the second process happens once the local energy concentration exceeds the energy equivalent of two electron masses.
The "inevitable" particle pair production in electromagnetic fields refers to the Schwinger effect, as far as I understand.
My question. Let's say we have a quantum field theory with a single massive particle.
- This massive particle exhibits gravity, right?
- So the "local energy density" (even though I don't quite understand how this is defined exactly since the stress-energy tensor is an operator, not a number, right?) should be bigger than the rest mass of the particle times the speed of light squared. (Is this also correct?)
- If that is so, then, according to the paragraph above, there would be pair production of electrons at the cost of the energy of the gravitational field caused by the massive particle whenever the mass of the massive particle is bigger than twice the mass of an electron.
- But what can loose energy here? The massive particle can't have any energy below its rest mass energy by definition.
- Furthermore, if electrons are emitted, they also exhibit gravity, correct? Where do the corresponding gravitons come from?