According to this wikipedia entry:

Young's modulus is the ratio of stress, which has units of pressure, to strain, which is dimensionless; therefore, Young's modulus has units of pressure.

From my reasoning if something is dimensionless, it should be a unitless ratio. So how come Young's modulus has a unit?

  • 1
    $\begingroup$ Because that article has punctuation problems, will delete this question. Once you read this. $\endgroup$ – GuySoft Jun 5 '13 at 12:17

Young's Modulus isn't dimensionless!

It says STRAIN is dimensionless (which is true).

SO Y = Stress/Strain = [Pressure]/[Dimensionless] = [Pressure]!

Young's Modulus has the same dimensions as that of pressure, which is:

$[M] [L]^{-1} [T]^{-2}$

And units of pressure, which is Pascal.

  • 1
    $\begingroup$ Hi mikhailcazi. Welcome to Physics.SE. This site uses an unique TeX markup style called MathJax. This markup is very useful for understanding math equations and parameters. Please have a look here for an intro or our FAQ for more info. For example, $\theta$ results $\theta$, $\omega$ inserts $\omega$, etc. It's quite interesting. You can revise your post if you can ;-) $\endgroup$ – Waffle's Crazy Peanut Jun 5 '13 at 14:22

Not the answer you're looking for? Browse other questions tagged or ask your own question.