# A small black hole asymptotically approaches a big black hole's event horizon. Will it seem to be frozen there, or will it seem to merge?

On this site, there are currently two scenarios described:

1. two black holes merge in a finite time

in any sensible meaning of the term merge the two black holes do indeed merge in a finite, and very short, time.

So Black Holes Actually Merge! In 1/5th of a Second - How?

2. anything falling to a black hole's event horizon will seem to be frozen there

Indeed, nothing can get under the horizon. The stuff close to the event horizon does move outwards as the black hole radius increases. Even more with any black hole deformations such as waves on its surface, the tidal deformations or the change of the rotation speed, all the objects close enough to the horizon remain "stuck" to it and follow all the changes of the black hole form.

How can anything ever fall into a black hole as seen from an outside observer?

So basically, the first one says, that two black holes will merge in a finite time from an outside observer's view (in fact we have witnessed black hole mergers and the gravitational waves coming from them), and the second one says that anything approaching the horizon will remain stuck to it (seem to be frozen there).

Now I cannot resolve this, because if a small black hole approaches a bigger black hole, then they should seem to merge in a finite time, but the small black hole should seem to be frozen at the event horizon of the bigger one. These two scenarios cannot seem to happen at the same time. We should either see the holes merge, and a common horizon to be created in a finite time, or we should see the small black hole to be frozen at the event horizon of the bigger one. I do understand that black holes are black, but they do have photon spheres and accretion disks, so the merger or the frozen state should be clearly distinguishable.

Which one will we observe? A merger, or a smaller black hole frozen at the event horizon of the bigger one?

A small black hole asymptotically approaches a big black hole's event horizon. Will it seem to be frozen there, or will it seem to merge?

You shouldn't take "frozen at the horizon" to mean that an extended body will appear to freeze as soon as the front end of it reaches the horizon, and retain its shape. Rather, the front appears to freeze as it nears the horizon, and the back also appears to freeze as it nears the horizon, so the object ends up seeming to be flattened against the horizon (Lorentz contracted, if you like; that's a fairly apt analogy since the object also appears redshifted as though it was receding rapidly). Meanwhile, the event horizon expands by an amount corresponding to the mass of the infalling object. This starts as a bulge at the location of the infalling object but it also flattens quickly.

When two black holes merge, essentially the same thing happens. If the smaller hole glowed brightly enough to be seen, you would see it pancake on the horizon and redshift to invisibility much like an ordinary object of the same size and temperature. The event horizon of the smaller hole becomes a bulge in the horizon of the combined hole which then flattens out.

• Thank you so much! The reason I am asking is because there are proposed animations of two holes merging where the two event horizons deform and join. But you are saying if I understand correctly, that the smaller hole will just be flattened and become invisible? Oct 8, 2021 at 5:19
• "If the smaller hole glowed brightly enough to be seen, you would see it pancake on the horizon and redshift to invisibility much like an ordinary object of the same size and temperature." - This is incorrect. A small black hole already is infinitely redshifted, so the fact that it approaches a big black hole does not affect the redshift. Furthermore, the small black hole will not be flattened. Numerical gravity shows the opposite - the horizons of both black holes extend and protrude toward each other until they unite like two soap bubbles: youtube.com/watch?v=Y1M-AbWIlVQ Oct 8, 2021 at 5:36

These are two different situations.

When an ordinary object falls into a black hole, The black hole curves spacetime. The object is assumed to not curve spacetime. A typical solution is given by the Schwarzschild metric. In that solution, as seen by a distant observer, the object takes an infinite time to reach the event horizon.

When a small black hole is dropped in, both objects curve spacetime. The small black hole is not going to get arbitrarily close to the big event horizon without disturbing it. The metric between the black holes is not well described by the Schwarzschild metric. They will merge.

• Thank you do much! "The black hole curves spacetime. A typical solution is given by the Shwarzchild metric. The object does not.", do you mean that the object only curves spacetime very little (relatively)? I believe everything with stress-energy curves spacetime. Oct 8, 2021 at 1:49
• @ÁrpádSzendrei I think that the object here refers to a test particle, which is assumed to not curve spacetime. Oct 8, 2021 at 2:54
• @ÁrpádSzendrei Yes, too little to make any difference. Good answer +1 Oct 8, 2021 at 5:39
• This doesn't correctly answer the question. There is no meaningful difference between a test particle and a massive object in this situation. Both appear to freeze at the horizon. Oct 8, 2021 at 5:56
• This fails to take into account the redshift and subsequent failure of the geometric optics approximation for the object falling through the horizon. Realistically, a distant observer will not see the "object freeze at the horizon", it will see to object rapidly fade and blur from view in a fraction of a second (the same timescale as the merger takes). Oct 8, 2021 at 7:37

I would like to add another answer that gets at this another way. I am not totally sure of this answer. If anyone has corrections, I would like to hear about it.

Suppose two black holes approach each other and freeze in place without actually merging, as described in Nathaniel's answer to How can anything ever fall into a black hole as seen from an outside observer?.

This is not a spherically symmetric distribution of matter. We should see an asymmetric gravitational field. If the pair are rotating, we should see gravitational waves continue to be emitted. We should see oscillations in the positions of background stars. We should see interesting effects in any accretion disk.

Because light can't escape the gravity of black holes, the whole event should be invisible, with the light being held in by the black holes. Any other matter falling in from the other side, at an angle where the light can get past the black hole without being captured would appear blue shifted and sped up by the Doppler effect, so it would be seen falling in if the light is able to get past the black hole when that close. Light from matter falling in from the observers side would become infinitely red shifted and invisible as the matter approached the speed of light. So, while, theoratically, it would appear plastered on the horizon, you wouldn't see it.