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I was working through Griffiths' Introduction to Quantum Mechanics, specifically the part about the 1D infinite square well potential (situated between $x = 0$ and $x = a$). To my understanding, this allows for multiple wave functions, each associated with a discrete level of energy:

$$\Psi_n(x, t) = \sqrt{\frac{2}{a}}\sin\left(\frac{n\pi}{a}x\right)\,e^{-i\frac{E_n}{\hbar}t}$$

where:

$$E_n = \frac{n^2\pi^2\hbar^2}{2a^2m}.$$

This is where it starts to get confusing to me. Does this mean that only one of these wave functions describes the particle state? Or is it that a general solution can be obtained by combining all the above possible wave functions to get the following one:

$$\Psi(x, t) = \sqrt{\frac{2}{a}}\sum_{n=1}^{+\infty}C_n\, \sin\left(\frac{n\pi}{a}x\right)\,e^{-i\frac{E_n}{\hbar}t}$$

This is how the textbook says the general solution is determined, but what's confusing me, in this case, are the $C_n$'s (the equation was taken directly from the book). How did they get here, even though they were not present in the first equations? And how are we to determine them?

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  • $\begingroup$ Hint (to see what the $C_n$ are): Calculate $(\Psi_n,\Psi)$, i.e. the scalar product between $\Psi_n(x,t)$ and $\Psi(x,t)$. $\endgroup$ Commented Oct 3, 2021 at 14:35

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I have now understood that the general solution is not simply a sum of the stationary states, but rather a LINEAR COMBINATION of the stationary states, thus the presence of the $C_n$'s.

I also understood that the way to compute the $C_n$'s is to use the orthogonality of the stationary states to get:

$$C_n = \int_0^a\Psi(x,0)\psi_n^*(x)dx$$

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  • $\begingroup$ Indeed, though it should be stated it is because the Schrödinger equation is a linear PDE. $\endgroup$
    – Triatticus
    Commented Oct 3, 2021 at 23:04
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Those wavefunctions (note: not "wave equations") are the energy eigenstates of the infinite square well. A general solution can be written as a linear combination of the eigenstates, where the coefficients of that linear combination are determined by the initial conditions set up by the physical situation. Any particle state described by a single energy eigenstate will evolve trivially in time (that is, it's probability distribution will not change in time, it merely picks up a complex phase). By contrast, a particle state describe by a linear combination will evolve in time: its probability distribution will appear to change due to beating between the eigenstates make up the linear combination that describes the physical state, each of which evolves with a different characteristic frequency.

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