What is the emf in this circuit? There is an infinite solenoid with radius $r$ inside the first loop powered by a current that changes over time so that the magnitude of the magnetic field inside the solenoid is $B(t)$. According to Faraday's law this generates an emf in the circuit, given by:
\begin{equation}
\mathcal{E}=-\frac{d\Phi}{dt}=-\pi r^2\frac{dB}{dt}
\end{equation}

This is equivalent to an emf generator. My guess is that the correct configuration is

where the cell provides an emf $\mathcal{E}$ as above. In a book I have, though, the solenoid is considered equivalent to the following configuration:

Where each cell provides an emf $\mathcal{E}'=\frac{\mathcal{E}}{4}$. This situation is clearly different and yields different results for the currents running in the loops. Actually, the left loop is no different mathematically, while the second loop is because of the generator in the common branch.
What is the correct configuration and why?
I thought that Faraday law should apply both to the left loop and to the big loop including the right and the left loop, this is why the first configuration looks fine to me.
EDIT: here is the figure in the textbook (readcomments in the accepted answer for more information). Sorry for the quality.

 A: You are correct. The emf is present in the left hand loop and the outer loop, because the changing flux is linked with both these loops. There is no net emf in the right hand loop, because no (changing) flux is linked with it.
It is therefore fine, for purposes of circuit theory, to represent the emf as if it were concentrated in the place you have shown (or in the left hand vertical line of the circuit or the left hand of the bottom line).
[We can understand where the textbook writers were coming from. They see the left hand loop surrounding the solenoid and believe that there ought to be emfs in all four sides of the square, including in the wire containing R2. They are forgetting that, applying the same reasoning to the outer loop, there ought also to be a 'downward' emf in R3, as well as emfs in other parts of the loop. So the emf they have shown in the wire containing R2 is not, on this viewpoint, the only emf in the right hand loop – and we know that the resultant emf in the right hand loop is zero. In general it is unsafe to argue in terms of emfs other than resultant emfs in loops.]
Which book gave you the other answer?
