# Linear wave superposition along a rope/string

This question basically roots to fundamentals of waves which is quite difficult for me to visualize. Hope that I can clear out this confusion based on answers to this question

Would be grateful if someone atleast verifies whether my own answer below is correct or not

suppose the green line in the image is a string. black dots were drawn to represent particles along the string and the red/blue ones are the displaced(due to wave) particles. Lets say two waves emerged at the two ends of the string and met at the particle $$g$$. These two waves are of same amplitude and same frequency. Aftermath of this superposition is that all these particles get displaced in the opposite direction nut at equal height after a very small period of time of the meeting of the two waves at $$g$$ and will move on like that.[All these assumptions are made for a very short period of time. I know that all the particles will return to equilibrium as soon as the energy is transfered completely to succeding particles]

Now the thing I didn't get is the progression of waves even after nullification of waves at $$g$$. I know that waves aren't nullified but they superimpose in such a way that the particle where they are meeting won't oscillate at all. But how does a mechanical wave propagate? It obviously needs a medium to propagate which in our case is the string. lets say we wanted to create a crest. In order to create that we lifted $$a$$ at the height of $$A$$ from the equilibrium position. As soon as we lifted that particle we immediately pulled it down. Now the particles adjacent to $$a$$ will also get a pull during the lifting but when we pulled $$a$$ down $$b$$ didn't go down immediately rather due to inertia it did reach at the height $$A$$ too. Succeeding particles will face same phenomenon. so to propagate a wave we observed that the preceding particles need to oscillate to transfer that energy to the succeeding ones through attraction, cohesion, adhesion or whatever. But what if a particle isn't oscillating? lets say particle $$e$$ is hold tightly so that it does not move at all. So it is unlikely that $$f$$ will oscillate rather it is more likely that the wave will reflect. Will the wave actually reflect back? If it does reflect, how does that reflect?(I can not visualize this one too nor does it seem to me intuitively understandable.) Lets forget holding anything and imagine that the two waves did meet at $$g$$. Now $$g$$ won't oscillate since these two waves are at opposite phase. so after the two waves end up at $$g$$ before the inversion as shown in the video of the link (https://www.youtube.com/watch?v=LJbpXx8fMUk), how does two waves again move from $$g$$ in two opposite direction? $$g$$ is supposed to remain static or oscillate but with a very low amplitude, how does it end up evolving waves of higher amplitude?

For this reason I am facing a lot of difficulty in understanding standing waves(how does wave propagate from nodal points if the particle at nodal point itself is not oscillating or is oscillating but with a very low amplitude?). I have looked for many sites for clearing out this confusion but could not find any satisfying answer or maybe I am too dumb to understand.

• You may wish to look at physics.stackexchange.com/a/211204/59023 Sep 9, 2021 at 12:50
• I did get the answer to reflection @honeste_vivere but didn't get the part of superposition.
– MSKB
Sep 9, 2021 at 16:43