# Free Boson on Torus - Partition function

I am currently reading Section 10.2 of the Yellow book by Francesco et al. They have shown in Equation 10.16 that $$$$Z_{bos}(\tau) = \sqrt{A} \ \prod_{n} \left (\frac {2\pi}{\lambda_n}\right )^{1/2}$$$$ where $$\lambda_n \neq 0$$. From now we will ignore the $$2\pi$$ term in the numerator. To calculate this, the book says we use Zeta function regularization technique. They define $$$$G(s) = \sum_{n} ' \frac{1}{\lambda^s_n}$$$$ where prime sum means that $$\forall n, \lambda_n \neq 0$$. As it is clear, at $$s = 0$$, $$G(s)$$ is not properly defined so we have to analytically continue to lower value of $$s$$. However, the book says in Equation 10.18 that $$$$Z_{bos}(\tau) = \sqrt{A} \exp\left(\frac{1}{2}G'(0) \right)$$$$ I am not sure how they arrived at this conclusion.

• Do you know how to differentiate? Jul 27, 2021 at 16:42

Note that: $$$$G'(s)=-\sum_n ' \ln( \lambda_n)\times e^{-s\,\ln(\lambda_n)}$$$$ Then you have trivially: \begin{align} Z_\text{bos.}&=\sqrt{A}\, \left.\exp \left( \frac{1}{2}G'(s)\right)\right|_{s=0} \\ &=\sqrt{A} \exp \left( \frac{1}{2}G'(0)\right) \end{align}