In the book, Feynman lectures (Part 1, Section 18; 18–2: Rotation of a rigid body), the author says: $$∆W = (xF_y− yF_x)\Delta\theta$$ where $xF_y−yF_x$ is torque. He also says:
Now let us consider a single force, and try to figure out, geometrically, what this strange thing $xF_y−yF_x$ amounts to. In Fig. 18-2, we see a force $F$ acting at a point $r$. When the object has rotated through a small angle $\Delta\theta$, the work done, of course, is the component of force in the direction of the displacement times the displacement. In other words, it is only the tangential component of the force that counts, and this must be multiplied by the distance $\Delta\theta$. Therefore we see that the torque is also equal to the tangential component of force (perpendicular to the radius) times the radius.
How can I relate (mathematically), $xF_y−yF_x$ with the tangential component of force (perpendicular to the radius) times the radius?