Do perpendicularly polarized waves interfere? In the MIT ME optics OCW slides, it is written that parallel polarized waves do interfere but perpendicularly polarized waves do not interfere. However, isn't circular polarization formed by the interference of 2 perpendicularly polarized waves with some phase difference?
 A: The issue is that "interference" can be taken to mean different things.
On a general footing, you can think of "interference" as any effect that results from the coherent combination of different waves. This covers e.g. the creation of circular polarizations by combining orthogonal linear polarizations at the correct relative phase.
But more specifically, "interference" is often understood in a more restricted sense as referring only to increases or decreases of the total observed intensity as a result of the superposition of two different waves. In this case, the MIT OCW resource is correct: constructive and destructive interference does not occur for perpendicular polarizations but it does occur for parallel polarizations.
The definition you gave in the comments,

interference is the superposition of the amplitudes of waves

is rather vague. Are you thinking of the amplitudes as vectors? Is the superposition required to increase or decrease the total (norm of the vector) amplitude? The answer to the question (i.e. whether perpendicular polarizations "interfere") will depend on how you specify those details.
(Or, in other words, it's all semantics.)
A: Electromagnetic waves will interfere with others if  their direction of polarization is not perpendicular.
Note that the amplitudes of electromagnetic waves have a particular  direction in space (perpendicular to the direction of propagation). The interference of such waves depends on their relative polarization directions, and the total intensity$^1$ for two linearly polarized EM waves is given by $$I = I_1 + I_2 + 2(I_1I_2)^{\frac{1}{2}}\cos(\Delta\phi)$$ where $\Delta\phi$ is relative angle of the two waves.
We can see that if $\Delta\phi=90^o$ the third term goes to zero (the intensities simply add up so that there is no interference, as oppose to the case where $\Delta\Phi=180^o$ in which case there will be interference).
And the superposition of two linearly polarized light waves with perpendicular polarization components, can result in linear, elliptical, or a circular polarized wave, but this depends on the amplitudes and the phase difference between polarization components of the two waves. See quarter wave plate.
$^1$ Intensity is proportional to the square of the amplitude.
