I am constructing the interference of two Gaussian wave packets onto which I apply a complex phase, attempting to obtain the coherence measure C (how well they overlap).

enter image description here

The $\Delta x(T)$ term in the argument represents the spatial splitting of the packets (as a real phase) and the complex exponential one between the two is my main concern, as, usually, it leads to a simple real value of C:

enter image description here

However, for a special case when the two $\Delta x(T)$ terms are taken to be different, it leads to a complex phase outside the integral:

enter image description here

where the complete formula for C now becomes a super long one with the terms inside the integral leading to a real term (as any complex term resulting from the complex exponential takes the form of a sine which cancels-out in the even integral above).

The point is that I do not understand the meaning of a complex or even a negative coherence measure C (which is meant to represent the overlap of the packets). As seen in the picture below, the overlap is easy to interpret and a negative value of C simply implies reflecting the graphs on the x-axis. But my question is how can I interpret a negative value of C?

And just as importantly, what about a complex value of C?

enter image description here enter image description here

I apologize for the lengthy and perhaps odd question, but I really found it versing and had to explain it well.

  • $\begingroup$ Can you show us what you are doing? If you type out the equation you are confused with it will be much easier to follow. $\endgroup$ Jul 13 at 13:11
  • 1
    $\begingroup$ @AccidentalTaylorExpansion It is quite lengthy, I'm afraid, which is why I did not include it initially, but I will edit my question accordingly now. Thanks for the comment. $\endgroup$
    – Vlad Ispas
    Jul 13 at 13:13
  • $\begingroup$ @AccidentalTaylorExpansion I hope this makes my question clearer (and yet another quick edit I just made). ^^ $\endgroup$
    – Vlad Ispas
    Jul 13 at 13:33

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.