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This question already has an answer here:

Can someone provide a derivation of the Biot-Savart law for electromagnetic induction? To be clear, $$ d\vec{B}~=~\frac{\mu_0}{4\pi}\frac{I d\vec{\ell}\times \vec{r}}{r^3}. $$

Is there a simple way to compute the magnetic field at a point between two Helmholtz coils, if the radii of the coils are the same and the current through each coil is the same?

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marked as duplicate by Qmechanic May 10 '14 at 16:26

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    $\begingroup$ What should the law be derived from? $\endgroup$ – David Z May 16 '13 at 3:24
  • $\begingroup$ @DavidZaslavsky, From Ampere's Law, preferably. $\endgroup$ – Reuben Stern May 16 '13 at 18:15
  • $\begingroup$ I consistant derivation would be interesting to see. This is a good conceptual question, I absolutely dont seevwhy 2 closevoters think this should be closed. $\endgroup$ – Dilaton Jun 9 '13 at 7:33
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    $\begingroup$ I dont understand why has this question been marked as aduplicate when the question given in the link is actually a duplicate of this question! $\endgroup$ – Karan Singh Jul 24 '15 at 16:18
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In the static case you can solve Maxwell equations using a vector potential via the poisson equatuion for the magnetic potential.

$\Delta \vec A(\vec r)=-\mu_0 \vec J(\vec r)$

Using the Greens function for the Laplace operator yields the solution of this differential equation.

$\vec A(\vec r)=\frac{\mu_0}{4 \pi}\int d^3r' \frac{\vec J(\vec r')}{|{\vec r-\vec r'}|}$

Now we can calculate the B field via $\vec B = \vec\nabla \times \vec A$ and use the identity $\vec\nabla\times(\phi\vec A)=\phi(\vec\nabla\times(\vec A))-\vec A\times\vec\nabla\phi $. Additionally we have to calculate the gradient of the scalar function 1/|(r-r')|. This gives the Bio Savart law.

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    $\begingroup$ What is '$rot$'? Furthermore, I am not convinced that you can do what you have stated. I want to see the entire thing! $\endgroup$ – MoonKnight May 16 '13 at 8:05
  • $\begingroup$ rot is the german word of curl, I'm sorry for that. Which point is not clear or what do you think I can not do? $\endgroup$ – Noldig May 16 '13 at 8:16
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    $\begingroup$ I don't see how you can derive the full expression from what you have said... $\endgroup$ – MoonKnight May 16 '13 at 8:23
  • $\begingroup$ @Killercam: you can get to the Biot-Savart law from Noldig's answer for the vector potential by using explicitely cartesian coordinates and vector basis. $\endgroup$ – gatsu May 16 '13 at 9:14
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It is an experimental law not derivable from other more basic laws

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    $\begingroup$ I think this is wrong. You can derive it directly from Maxwell equations, which are more fundamental from my point of view. $\endgroup$ – Noldig May 16 '13 at 7:16
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    $\begingroup$ And how do you think Maxwell equations have been obtained? I think from Coulomb and Biot-Savart laws! $\endgroup$ – richard May 16 '13 at 8:29
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    $\begingroup$ ok, historically you are correct. Let's say they follow from each other, or they are consistent. $\endgroup$ – Noldig May 16 '13 at 8:50
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    $\begingroup$ OK,people! Historically, Biot-Savart's Law -> Maxwell Equations -> Special Relativity But, I think now, you'll all agree that Special Relativity is the most fundamental of them all. So, why not use Special Relativity to give derivation of Biot-Savart's Law? I think I might write an answer $\endgroup$ – Cheeku Jul 11 '13 at 23:14

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