# Determine the change of charge in both capacitors

I have the following circuit

The switch has been open for a long time, and both capacitors are fully charged. After that, the switch is closed and the circuit is broken. I need to determine the change in charge $$Q$$ for each capacitor after a long period of time.

Why is that the change in charge through each capacitor is simply not the maximum charge each capacitor can hold? I see it like this. Each capacitor becomes fully charged and this charge can be determined as $$Q = CV$$. After the switch is closed, these capacitors begin to discharge through the circuit. However, after a long time has passed each capacitor completely discharges all of its charge as per $$Q(t) = VCe^{-\frac{t}{RC}}$$

• What you said seems right, all the charge will go, the resistances just slow things down... Jun 16 at 12:52
• No, there will be a voltage across each resistor, and hence across each capacitor. Do you know what a voltage divider is? Jun 16 at 13:21