We know that the electric field inside a conductor is zero, but in my book, according to Gauss' law, the electric field inside a solid sphere (it's not mentioned if it's a conductor or non-conductor) is $$E = \frac{Q}{4 \pi \varepsilon_0} \frac{r}{R^3}$$

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    $\begingroup$ This a sphere with a uniformly distributed electric charge, so obviously not a conductor. $\endgroup$
    – mike stone
    Commented Jun 8, 2021 at 12:02
  • $\begingroup$ Thanks :). Now I can go back to sleep :) $\endgroup$
    – Riyo
    Commented Jun 11, 2021 at 14:17


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