I tried to fit low baryon resonances to N(1440) in an SU(3) octet.
So I started with
$$\frac{N + \Xi}{2} = \frac{3 \Lambda + \Sigma}{4}$$
What should the respective $\Lambda (I=0), \Xi(I=\frac{1}{2}), \Sigma(I=1)$ be identified with?
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The PDG resonance listing to fish from for a lowest resonance baryon octet with 1/2+ visibly suggests
N(1440) ; Λ(1600) ; Σ(1660) ; Ξ(1690) ,
but, beware!, the cascade concluding the above list has not had its spin-parity fully identified.
Still, slipping in a strange quark crudely raises the energy by about 100 MeV as it is expected to, and the Gell-Mann--Okubo sum/difference you appear to be relying on (but why?), in MeVs, seems to zero out adequately, $$ 2(1440+1690) -3(1600) -1660 \approx -200. $$
answered Jun 6, 2021 at 16:14
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$\begingroup$ I used formula, because I wanted to check accuracy of linear Gell-Mann-Okubo relation for baryons, firstly matching octet to N(1440) with spin $J =1/2$ and parity $P = 1^+$. $\endgroup$ Commented Jun 6, 2021 at 20:20
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$\begingroup$ After the advent of quark models and QCD simulations, the G-M--O formula is somewhat "academic", however, no? $\endgroup$ Commented Jun 6, 2021 at 21:43