# Is there any phenomenon in physics which is sensitive to irrational numbers?

We can measure only rational numbers by our scale. Here is an example where irrational numbers does makes sense. If so then this question may have some theoretical importance. Is irrational numbers important for physics?

• Do you mean "sensitive to irrational numbers" but "not sensitive to rational ones"? $\pi$ and $\sqrt 2$ and $e$ show up all the time in physics. Are you imagining (for example) a process where if $\alpha$ were exactly $1/137$ things would be completely different than if it's an irrational number really close to $1/137$? – Brandon Enright May 10 '13 at 18:49
• Do you mean imaginary numbers? – DilithiumMatrix May 10 '13 at 18:51
• An example would be pseudo-random optical lattices! If you have a superposition of two standing waves with wave-lengths $\lambda_1$ and $\lambda_2$, then if they are truly incommensurable, the resulting standing wave is non-periodic and can be considered "random" or "disordered", whereas if they are commensurable, i.e., if their ratio is a rational number, the lattice is still periodic (albeit with a possibly large period) – Lagerbaer May 10 '13 at 18:53
• @BrandonEnright: although $\pi$ occurs very often, I've hardly ever seen $e$ as a pure number. Most often we use it by convention, for example instead of measuring the entropy as $S = k \ln \Omega$ we could just as well write $S = k' \log_{13} \Omega$ for some rescaled Boltzmann constant $k'.$ – Vibert May 10 '13 at 18:57
• These two types have different mathematical character. Is that difference proved important in any physical theory? @BrandonEnright – Self-Made Man May 10 '13 at 18:58

One of the directions to look at goes under the name of "commensurability". Imagine electrons that can travel on a two-dimensional lattice and suppose there is a constant magnetic field perpendicular to the lattice. Making a discrete loop on the lattice will add to the electron-wavefunction an Aharonov-Bohm phase propotrional to the area coverd by the loop. Resulting interference pattern will depend on the commensurability of the enclosed magnetic flux with the flux quantum $h/e$.