Are tidal power plants slowing down Earth's rotation? Are tidal power plants slowing down Earth's rotation to the speed of the orbiting moon? (1 rotation per 28 cca days) 
Are they vice versa increasing the speed of moon orbiting by generating some waves in gravitation field?
If yes, can you calculate how much energy must be produced by how many tidal power plants (compare it to average nuclear plant please) to slow down the Earth's rotation to 25 hours / day?
 A: In order to slow down the rotation of a body angular momentum must transferred off that body.  In the case of Earth and the moon this occurs from the difference in gravity across the Earth, or tidal force.  A tidal power generating system simply converts a tiny fraction of energy in the tidal bulge of the Earth, mostly in the oceans, as it moves around the globe into mechanical or electrical power.  The question is whether that induces a torque on the Earth.  
These systems might serve to reduce the tidal bulge of the oceans a very tiny amount.  So from the systems perspective the flow of water is impeded, the effective viscosity increased, friction increased and the tidal bulge reduced.  This represents a tiny amount of energy reduced on the Earth in this form.  However, this is a near infinitesimal amount of the Earth’s rotational kinetic energy.
A: I think that the effect of tidal power will be to (very slightly) to increase the tidal drag on the moon.
Consider the following thought experiment :
Imagine an idealised rigid planet with an idealised rigid moon. This planet has perfectly smooth valleys and hills in which a  friction-less ocean resides.
Tides will occur but the moon/planet system will not be orbitally slowed because there will be no net tidal energy loss - the moon will simply drag the friction-less ocean around the planet causing the moon's orbital speed to fluctuate up and down slightly as energy is exchanged back and forth slightly with the ocean tides. 
Now imagine a tidal power plant being installed - this will extract energy from the  moon/planet system as the falling water from the power plant must now lag in order to have a height difference between input and output water levels in order to produce power. This will have an overall drag on the moon since the water flowing out from the power plant will be displaced from the correct position to return all the energy back to the moon - thus affecting the orbital speed.
David B
A: In principle, yes, the ultimate source of energy for a tidal power plant is Earth's rotational energy, so these plants are slowing down the Earth's rotation. By conservation of angular momentum, that means they are pushing the Moon further away as well, although I wouldn't phrase it as being due to "waves in the gravitational field," as that expression suggests a different phenomenon.
The Earth's rotational kinetic energy is about $10^{29}$ J, and the world uses something like $10^{22}$ J/year, so you could power the entire world for millions of years before you'd run out of rotational energy.
To answer your numerical question, you should work out the rotational kinetic energy of the Earth now, and also when the day is 25 hours long. The difference between those is the total energy required. The way to figure out the rotational kinetic energy is ${1\over 2}I\omega^2$.  Here $I$ is the Earth's moment of inertia, which is about $0.4MR^2$ where $M$ and $R$ are Earth's mass and radius. $\omega$ is the Earth's rotation rate in radians per second -- that is, $2\pi$ over the time for one rotation.
