I don't understand this phenomena pointed out in LDO's Capacitor vs. Capacitance where it says:
Given the dynamic nature of capacitors (storing and dissipating electric charge in a nonlinear fashion), some polarization may occur without the application of an external electric field; this is known as “spontaneous polarization.” Spontaneous polarization results from the material’s inert electric field, which gives the capacitor its initial capacitance. Applying an external DC voltage to the capacitor creates an electric field that reverses the initial polarization and then “locks” or polarizes the rest of the active dipoles into place. The polarization is tied to the direction of the electric field within the dielectric. As shown in Figure 1, the locked dipoles do not react to AC voltage transients; as a result, the effective capacitance becomes lower than it was before applying the DC voltage.
When applying a DC voltage across a capacitor, all dipoles should align with the positive (negative) end of the dipole pointing the negative (positive) plate. Like charges repel and opposite charges attract, and the dipoles should point one way or the other. But in the image shown, the locked dipoles align with the electric field, and the active dipoles ignore the electric field. So a locked dipole can rotate and an active dipole cannot rotate ... What exactly is a locked dipole and an active dipole?
Why won't a locked dipole react to AC transient? If an AC polarity goes one way, the dipole will point to that direction. The dipole should reverse its direction if the AC polarity changes.
I still don't see the physics behind how a DC voltage (or AC) derates the capacitance.