# How does diffraction affect the amplitude of sound?

Let’s say we have a 2D “maze” which represents walls in a space. If we place a sound source somewhere in it, what would be the amplitude at a different point in the maze. Or in a simpler case, given a sound source, a wall (possibly enclosing it from all sides but with a gap), and a sound receiver along the outside wall, how do I calculate the amplitude there.

I found sources online saying that amplitude does decrease after diffraction but none about how exactly I calculate it.

• Do you let your source run indefinitely? Is it a wave with a single frequency? May 15 at 18:49
• Well, let's say that its a constant frequency wave and it emits only for a short while, so only the immediate results are considered from the diffraction May 16 at 10:48
• If it's a pulse it can't be made of a single frequency. May 16 at 16:59

$$\nabla^2 P = \frac{1}{c^2} \frac{\partial^2 P}{\partial t^2} + F(x, y, t)\, ,$$