# How are relativistic tidal forces different from their Newtonian counterparts?

Conceptually, the tidal effects of Newtonian gravity differ drastically from that of general relativity. In Newtonian gravity, the effect is due to the change in gravitational force across a certain distance, while in general relativity it corresponds to geodesic deviation and is a result of curvature.

However, from how I see it, they are not very different mathematically.

The Newtonian tidal equation is derived by making a Taylor expansion of the gravitational field.

$$a\approx 2 \Delta r ~G\frac{M}{r^3}$$

The relativistic one uses the geodesic deviation equation and the Riemann curvature tensor for the Schwarzschild metric.

$$a = \Delta r ~\frac{r_s}{r^3}\approx 2 \Delta r ~G\frac{M}{r^3}$$

They both seem to give the same result, even in regions that relativistic descriptions should seem to dominate, like near a black hole. For example, the calculation of the Roche limit of a black hole seems to be identical to that of a more Newtonian object like a star.

Am I missing something here? Am I being too liberal with the "$$\approx$$" sign? Perhaps there are regimes in which relativistic tidal effects are dramatically different from Newtonian? Or do they differ only conceptually, but in fact produce the same numbers?

• Firstly, could you elaborate on how our questions are the same? Mine has nothing to do with micro black holes Secondly, was my comment inaccurate? I simply quoted the article you linked. May 13, 2021 at 1:44

In the weak-field limit, GR and Newton give the same result. You have only shown the radial component of the tidal tensor:

$$E_{\hat r\hat r} = -\frac{2M}{r^3}$$

There are also two angular components:

$$E_{\hat{\theta}\hat{\theta}} =E_{\hat{\phi}\hat{\phi}}=+\frac{M}{r^3}$$

which induces a volume-preserving squishing along with the radial stretching. Volume is preserved because the tidal tensor is traceless:

$$E_{ij} = J_{ij}-\frac 1 3 J_{kk}$$

with

$$J_{ij} = \frac {d^2U}{dx^i dx^j}$$

being the Hessian of the potential $$U(r)$$.

In GR, one starts with the Weyl curvature tensor, $$C_{\mu\nu\sigma\lambda}$$. The Newtonian tidal force along a geodesic is reproduced by

$$E_{\mu\nu} = u^{\sigma}u^{\lambda}C_{\mu\sigma\nu\lambda}$$

which is called the gravioelectric tensor.

The frame-dragging (and velocity dependent) part, unique to GR, is described by the graviomagnetic tensor:

$$H_{\mu\nu} = \frac 1 2 u^{\sigma}u^{\lambda}\epsilon_{\alpha\beta\sigma(\mu}C^{\alpha\beta}_{\ \ \,\,\,\nu)\lambda}$$

While $$E_{\mu\nu}$$ leads to differential stretching and squishing, $$H_{\mu\nu}$$ leads to differential twisting (frame-dragging).

Such things are hard to visualize, so the integral curves of the eigenvectors of these tensors are used. They are called tendex lines and vortex lines, respectively (see figure). • Does the gravioelectric tensor agree with the Newtonian tidal tensor even outside the weak field limit? In other words, is the graviomagnetic tensor the only new effect introduced by GR? May 12, 2021 at 16:39