Acceleration & geodesics in General Relativity Acceleration is a deviation from a geodesic so:
If a person is falling on earth that person is weightless (an inertial frame of reference, not accelerating) and he will see the people in the building going upwards with acceleration. So does that mean that the person falling down is following the path of geodesic as acceleration is a deviation from geodesic and the falling person isn't accelerating? And are the people on the building deviating from the path of geodesics since they are accelerating from the perspective of the falling person?
Please try to answer in simple words...
 A: 
so does that mean that the person falling down is following the path
of geodesic

Yes

as accleration is deviation from geodesic and falling person isn't
acclerating and are the people on the building deviating from path of
geodesics since they are acclerating?

When we say, the falling person isn't accelerating, it means something specific. After all, he is clearly accelerating towards the surface of the earth.
What we can say, is that he is not undergoing any "proper" acceleration. You said to answer in simple words, so in dumbed down terms,  proper acceleration is akin to the acceleration that he would measure on an accelerometer that he is holding. So, when he is falling, the accelerometer would show 0.
On the other hand, the guy in the building would have some reading on his accelerometer.
This is the sense in which we can say , that the falling guy is not accelerating and the building guy is accelerating.
A: Trajectories along geodesics aren't subject to other forces, so being stood on the ground or in a building doesn't constitute as geodesic motion.
