# Does Anderson localisation occur if the potential are equal in pairs?

Consider the Anderson model given by the Hamiltonian $$H \in B(l^2( \mathbb{Z}^d))$$ defined by $$H = - \Delta + V$$ where the potential $$V$$ acts on a unit vector $$\mid {x} \rangle \in l^2( \mathbb{Z}^d)$$ by $$V \mid {x} \rangle = V(x) \mid {x} \rangle$$ where $$V(x)$$ are i.i.d uniformly distributed in $$\lbrack 0,1 \rbrack$$. This system exhibits Anderson localization.

Now, if we put $$d=1$$ and I pick $$V(2x)$$ i.i.d uniformly distributed in $$\lbrack 0,1 \rbrack$$ and then let $$V(2x+1) = V(2x)$$. Does this system then still exhibit Anderson localization?