# What is the force of a wall on a revolvable rod?

I have a dilemma.
If I look at the diagram and say the sum of the forces in x and y direction has to be zero, then I will simply conclude that the force of a wall on a revolvable rod is the blue N as drawn.

But what if the force is actually the green N? To me, it makes more sense because if imagine no tension and no mass M, then the force of a wall N would be drawn as below (green N).

So how can I argue that the orange component of N does exist? If it exists...

• Did you try my suggestion? If so, what does it tell you about orange N? Apr 20 '21 at 12:00
• @BobD It does make sense. I just had a couple of confusing examples in my study book and the manual solution to one of them was wrong and it confused me. What I actually learned is that I have to look at different points on the body and as you wrote in the answer the sum of the moments have to be 0. It helps for future problems! Apr 21 '21 at 20:35

Note on the FBD the tension force and gravitational force on M do not contribute any moment (torque) about the point B. The two forces $$F_{g1}$$ and $$N_H$$ both create a counter clockwise moment about the B. For equilibrium, these moments must be balanced by an equal clockwise moment. The orange component of $$N$$, $$N_H$$, is needed to provide that clockwise moment.