How is many world interpretation of quantum mechanics compatible with no cloning theorem?

Question

In many worlds interpretation of the quantum mechanics all possible outcomes of a measurement are realized, however, in different universes. Everytime a measurement occurs we register one outcome and for the others our universe is copied and possible outcomes appears in these copies.

In quantum mechanics also holds no cloning theorem which tells that it is not possible to copy a quantum state. For example, on a quatum computer, it is not possible to construct a gate mapping state $|\psi\rangle \otimes |0\rangle$ to $|\psi\rangle \otimes |\psi\rangle$. It is only possible to use CNOT gate as a fan-out but in this case, the state $|\psi\rangle$ is in the end entangled with its "copy" (they are not independent).

Imagine, we do a measurement of a qubit for example, so only two possibe outcome can occur - $|0\rangle$ and $|1\rangle$. Assume that we measured $|0\rangle$ and rest of our universe remains unchanged. In many world interpretation, our universe has been copied with only one exception - the result of the qubit measurement is $|1\rangle$. These two universes are independent. So, how is this copying of universes compatible with no cloning theorem?

Answer 1

In the many-worlds interpretation, the measurement process amounts to the mapping \begin{align*} &\lvert\phi_\mathrm{system}\rangle\otimes\lvert\mbox{observer hasn't measured yet}\rangle \otimes \lvert \psi_{\mathrm{rest}}\rangle \\ &\qquad\mapsto\ \ \ a\lvert\mathrm{system}=0\rangle\otimes\lvert\mbox{observer sees }0\rangle \otimes \lvert \psi_{\mathrm{rest}}\rangle \\&\qquad\quad + b\lvert\mathrm{system}=1\rangle\otimes\lvert\mbox{observer sees }1\rangle \otimes \lvert \psi_{\mathrm{rest}}\rangle\ , \end{align*} with $\lvert\phi_\mathrm{system}\rangle=a|0\rangle+b|1\rangle$. This is perfectly unitary and entirely comparible with the no-cloning theorem.