Eve could use a polarising beam splitter (PBS) crystal instead of a regular polarising filter. The PBS does not destroy the photon, it simply directs vertical photons one way and horizontal photons a different way. Eve could potentially recombine paths and send the photons on to Bob, no matter which way they were initially polarised. The problem arises when Eve tries to determine which path the photon took, after passing through the PBS in order to determine its polarisation. Any attempt by Eve to demine the "which way" information will alter the photons properties in a way that can potentially be detected by Bob. so he could in principle determine that eavesdropping has taken place. For example, Eve could bounce the photon off a tiny mirror. Since photons have momentum, Eve could in principle detect the tiny recoil of the mirror as the photon bounces off it. However, this movement due to the recoil of the mirror will change the phase of the photon and if Alice was sending entangled photons via two paths to Bob, the change in phase will destroy the interference pattern seen by Bob and he will know know something dodgy is going on.
But how can Eve measure the polarization of a single-photon without
destroying it?
While eve can potentially measure the polarisation of a single photon without destroying it, any attempt to measure the polarisation will alter the polarisation to a certain extent, whether a PBS or a regular polarising filter is used and this is potentially detectable at the receiving end.
Alternatively Eve could direct the photons exiting the PBS to two detectors, so she will know the polarisation of the photon sent by Alice, but at the cost of destroying the photon with 100% certainty. Let's say she detects a photon on the vertical path. She could then create a vertically polarised photon to continue the journey in place of the destroyed photon. Unfortunately for Eve this attempt to eavesdrop undetected is not perfect, because she cannot create a exact copy of the photon she destroyed because of the "no cloning" theorem of QM and there would be a noticeable delay in the travel time of the photon.