# How is energy conserved in blueshifting?

I am having trouble understanding the conservation of energy in the scenario below.

A photon of $$\lambda_1$$ is emitted by a source and then absorbed by object 1 in space. Object 1 can be considered to have 0 velocity relative to the emission source. Object 1 captures 100% of the emitted photon's energy and uses it to preform work according to $$E=h/\lambda_1$$.

The same photon if it were captured by object2, which is traveling in space at a constant velocity of 50% speed of light towards the emission source, would observe $$\lambda_2<\lambda_1$$. Hence object 2 would capture more energy from the same photon, and it would be more energy than was lost to the photon when it was emitted by the source.

What am I missing here?

• Hello! I have edited your question using MathJax (LaTeX) math typesetting. For future questions, you can refer to MathJax basic tutorial and quick reference. Thanks! Apr 7 '21 at 16:55