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We charge a conductive sphere with charge $Q$. Charges on a charged conductive sphere go towards the surface so then the volume charge density is 0 which makes surface charge density $Q$. Is my statement right?

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  • $\begingroup$ I am not sure if you are missing something in your question, is it not obvious ? $\endgroup$ – Aditya Prakash Apr 3 at 13:52
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Surface charge 'density' will not be Q. It will be $\sigma=\frac{3Q}{4\pi R^3}$. Yes in a conductive sphere the charges will move towards the surface, ideally speaking the volume charge density will be 0 as a result.

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    $\begingroup$ Your formula gives the charge/unit volume, but the charge will be distributed on the surface of a conducting sphere: ρ = Q/(4π$R^2$) $\endgroup$ – R.W. Bird Apr 3 at 18:31

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