# Charge density in a conducting sphere

We charge a conductive sphere with charge $$Q$$. Charges on a charged conductive sphere go towards the surface so then the volume charge density is 0 which makes surface charge density $$Q$$. Is my statement right?

• I am not sure if you are missing something in your question, is it not obvious ? – Aditya Prakash Apr 3 at 13:52

Surface charge 'density' will not be Q. It will be $$\sigma=\frac{3Q}{4\pi R^3}$$. Yes in a conductive sphere the charges will move towards the surface, ideally speaking the volume charge density will be 0 as a result.
• Your formula gives the charge/unit volume, but the charge will be distributed on the surface of a conducting sphere: ρ = Q/(4π$R^2$) – R.W. Bird Apr 3 at 18:31