0
$\begingroup$

We were discussing a problem on the Resonance Tube Experiment in class when my teacher wrote down the following equations:

My teacher's figure

AN and N stand for the positions of the antinode and node, e stands for the end correction and l1, l2 and l3 are lengths of the tube in the three cases. What I am wondering is, why can't the end correction be applied inside the tube? Mathematically. why can't e be negative? Does this have anything to do with the reason for end correction?

$\endgroup$
0
$\begingroup$

The, e, assumes that the anti-node lies beyond the end of the open tube. Combining two of the resonance equations permits finding, λ, and, e; but you may find that e changes as, λ, gets smaller.

$\endgroup$
1
  • $\begingroup$ Is it physically possible for the organ pipe to exceed the length of the antinode? Why or why not? $\endgroup$ – Ambica Govind Mar 31 at 5:57

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.