0
$\begingroup$

enter image description here

According to the Cauchy Postulate, the stress vector (T)^(n) remains unchanged for all surfaces passing through the point P and having the same normal vector n at P i.e., having a common tangent at P. This means that the stress vector is a function of the normal vector n only, and is not influenced by the curvature of the internal surfaces.

source: Wikipedia https://en.wikipedia.org/wiki/Cauchy_stress_tensor#Cauchy%E2%80%99s_postulate

So, traction vector or stress only exist at internal surfaces? What about the external surface of the continuum body (boundary surface)?

Improve this question
$\endgroup$
3
  • 1
    $\begingroup$ Note that we use MathJax to typeset mathematics; you can find a good tutorial here. $\endgroup$
    – Emilio Pisanty
    Mar 29, 2021 at 13:36
  • $\begingroup$ Thank you Emilio for the reference $\endgroup$
    – user134613
    Mar 29, 2021 at 13:45
  • 1
    $\begingroup$ This follows from the principle of local action for the stress tensor. It only depends on the deformations at the immediate point under consideration. $\endgroup$
    – Chet Miller
    Mar 31, 2021 at 11:12

1 Answer 1

Reset to default
1
$\begingroup$

It doesn't matter whether the surface is internal or external, all what matters is that a traction vector is a unit surface vector that acts on the surface of a body ( particles at the surface) and not on the interior of the body. Otherwise it would a body force vector that acts on the interior of a body (example: gravity force vector).

Improve this answer
$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.