How much force applied to canal wall from that cargo ship given 220,000 tons and 12.8 knots? In case you've been hiding under a rock, or are reading this in the future: "that cargo ship" is a huge story right now (3/26/2021). A brief summary: well basically a few days ago one of the world's largest cargo ships somehow managed to dig its bulbous bow into the east wall of the Suez canal. The back end of the ship is resting on the west end and no other ships can pass. I read 220,000 tons and 12.8 knots https://www.baltimoresun.com/news/nation-world/ct-aud-nw-cargo-ship-stuck-egypt-suez-canal-20210324-oytkblgh5ngihlwitcy7hdsnwi-story.html and thought it might make a fun little physics question. Another one I thought of is how much volume of water that much weight displaces...
 A: If it can be determined what the stopping distance was for the ship, such as by a measurement of the depth of penetration of the ship into the canal wall, and can ignoring the resistance of the water to the ship movement, one can estimate the average impact force using the work energy theorem, which states that the net work done on an object equals its change in kinetic energy, or
$$F_{ave}d=\frac{1}{2}mv^2$$
Where $F_{ave}$ is the average impact force, $d$ is the stopping distance of the ship, and $v$ is the ship velocity just prior to impact.

if we use 50 meters as a guess we get 4,346,866,404.5 joules / 50m = 86,937,328 newtons
Hope this helps.
A: For the volume of water displaced...  Archimedes principle says that "a floating body displaces it's own weight of the liquid in which it floats".
So the cargo ship displaces 220,000 tons or 200,000,000 kg of water.  For a density of water of 1000kg per cubic metre that's 200,000 cubic metres of water displaced.
Apparently some other ships are detouring around the Cape of Good Hope, some detour!
