In science fiction you get neutronium which supposedly makes darn good armor--which of course has absolutely nothing to do with reality.

You hook up your Acme star spinner (pay no attention to the energy needed) and spin the star up so the surface gravity at the equator goes negative and start picking up the pieces.

At first you're going to get the normal matter that was on the outside, but once that's gone what happens? With the pressure removed it's obviously going to change state, but into what? Simple decay to hydrogen? Given the density this doesn't strike me as the right answer. Does it fuse to the lowest energy level, yielding iron and nearby elements? Given the neutron density do we get a massive r-process capture, giving us a radioactive hell of row 7 elements?

Edit: Based on what has been said so far I realize I'm not really describing it right.

The deepest parts of the surface matter obviously get quite a neutron flux and get pushed down the table and since there can't be solids at that point you will have mixing, it will push at least the denser stuff down the table at least to bismuth. How far into the surface that neutron flux goes would say how much of it gets converted.

The issue comes down to how fast that conversion happens. On a long enough time scale you get the sort of stuff that's thrown off by neutron stars going splat (but does that actually contain a bunch of stuff past bismuth that decays before we see it?), but what time scale is that? As we pull off fresh stuff how far along the process does it get?

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    $\begingroup$ Note that material is ejected from neutron star surfaces during mergers, so this calculation has actually been done carefully. $\endgroup$
    – rob
    Commented Mar 24, 2021 at 16:13
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    $\begingroup$ @rob Surfaces, yes, but I'm wondering about what happens to the deeper material when the pressure is removed. $\endgroup$ Commented Mar 24, 2021 at 18:45
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    $\begingroup$ Whatever it is you get, you won't have much time left to enjoy it. $\endgroup$ Commented Mar 26, 2021 at 10:17
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    $\begingroup$ The correct answer to the title question is: Squished. $\endgroup$
    – Lee Mosher
    Commented Mar 26, 2021 at 22:25

5 Answers 5


This is not really mining, as the neutrons and protons and electrons in the inside of a neutron star recombine to give you nuclei when the pressure drops to zero. The solid crust of a neutron star contains (very heavy) neutron-rich nuclei arranged in lattice domains. At the interface between the core and the crust you have the so-called pasta phase (highly deformed nuclear clusters). All this stuff is comprised of neutrons and protons (the fraction between the two changes as you go deep, increasing the pressure). Charge neutrality is guaranteed by a sea of relativistic electrons, more or less like in a metal, but with a lattice of exotic heavy nuclei. Differently from the terrestrial solids, these neutron-rich nuclei are fully ionized.

The thumb rule is: as you compress, proton and electrons combine to give more and more neutrons. Finally, after the pasta you reach the core: this is a homogeneous fluid comprised of protons, neutrons and relativistic electrons (homogeneous cold catalyzed nuclear matter). This makes sense: the nuclear clusters are so compressed and close that they merge together in a homogeneous fluid. Some muon may appear (the exact density at which this happens is debated and depends on the still unknown details of the nuclear strong force). As you go deeper and deeper things are uncertain: you may find hyperons, a quark-gluon plasma, or other exotic stuff (we really do not know).

All this stuff exists because of the pressure and temperature conditions in a neutron star interior: remember that (differently from the atomic nucleus) a neutron star is held together by gravity, not by nuclear forces (nuclear forces create the pressure needed to sustain it against gravity). So, when you spin a neutron star up, you also change its density and pressure profile, changing also the composition (beta reactions take place).

In general, catalyzed nuclear matter has the tendency to recombine to give you the "usual" elements when you lower the pressure (or density): as @rob pointed out in the comments, this is well studied because of neutron star mergers (part of the matter is ejected and gives you metals like gold, platinum and many other elements.. this is called kilonova).

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    $\begingroup$ You are describing how a neutron star is built, I'm wondering what you get when you take it back apart. Of course the normal matter near the surface has been undergoing neutron capture--if you wait long enough you obviously get row 6/row 7 elements. But what's the timeframe to push the surface matter that far down the table? $\endgroup$ Commented Mar 24, 2021 at 18:48
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    $\begingroup$ It depends how fast you spin up the star. If you spin up it slowly, then when you reach the mass shedding limit you start ejecting the outermost layer that is made of Iron. When this layer is ejected, the subsequent layer will be transformed into iron as well... etc etc.. so in the end if you spin up it slowly you will just end up with a lot of Iron (in the early stage of the process, then the neutron star stops being a neutron star because its central density will be so low that complex recombination will take place). $\endgroup$
    – Quillo
    Commented Mar 24, 2021 at 19:43
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    $\begingroup$ Surely I can't be the only person who saw the title of this question and hoped the answer was going to be "another day older and deeper in debt". $\endgroup$ Commented Mar 25, 2021 at 18:17
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    $\begingroup$ @AdmiralJota yeah, but if you say that, someone will just delete the comment. :( That was my first thought, though. $\endgroup$ Commented Mar 26, 2021 at 0:59
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    $\begingroup$ @Quillo For everything to decay to iron you may have to wait a very very very long time. I mean, not quite proton decay heat death long time, but much much longer than the time since the big bang until now. "slowly" heh. $\endgroup$
    – Yakk
    Commented Mar 26, 2021 at 18:49

If you remove the pressure the material will just do its best to get to the state that has the overall lowest energy density.

Things that certainly will happen are that neutron-rich materials from the neutron star crust will just beta-decay back towards the low-density nuclear stability line. If those elements are super-heavy then they will be unstable to fission. Ultimately I would think you would get a mixture of heavy (heavier than iron), but stable elements.

This applies to the crustal material, but the point is that as you remove material from a neutron star, its mass diminishes and hence its radius increases. The surface gravity and pressure decrease and what was in the deep interior at high densities is now closer to the surface and at lower densities. This material will become crustal material if you allow that process to happen slowly enough that it can be done in pseudo-equilibrium conditions.

If you do it quickly then you are likely to get a fierce bonfire. That is because removing the pressure allows more protons and electrons to be produced from neutrons, but the protons are going to be able to start fusing with neutrons in electron-degenerate conditions. Whilst this is going to proceed very quickly and then carry on through subsequent fusion stages, there isn't enough energy there to unbind the star - so no catastrophic event, just a raging inferno on the surface.


As Quillo ProfRob and John Doty already pointed out, the general mining problem is that the dense matter in a neutron star will decay/transform as the pressure (or equivalently in this case: baryon chemical potential) drops.

Well, there is an exception for the stability argument at lower pressures, especially for neutron stars. The existence of Strange Stars is discussed in the field of nuclear astrophysics, which is a star containing (or purely being build of) matter containing strange quarks. It is also discussed that strange quark matter is absolutely stable, even at zero pressure (in media, this idea became known more widespread with the concept of "Strangelets"). Let's ignore for one second that both (existence of strange stars, stability of strange matter at zero pressure) assumptions are far from being settled facts, the neutron star mining idea is a promising way to obtain strange matter.

[I totally agree that this answer contains, although being seriously discussed in the field of nuclear astrophysics, more speculative aspects of compact stars. I felt that this added a useful information here because the question mentioned "science fiction" in the first paragraph.]


What happens to decompressed deeper material is that it decays into a soup of nuclei and neutrons, which then sort themselves out via the R-process. The result is neutron-rich radioactive heavy elements that beta decay into more stable elements over time.


The neutron star matter is a good model of what the universe looked like in the first few micoseconds after the Big Bang, just after the baryogenesis.

The neutrons in a neutron star are kept from decaying by the degenerate electron gas (both neutrons and electrons, as well as protons at some depth and below, are degenerate in a neutron star). Inserting an electron in this electron gas requires energy that the beta decay cannot supply.

If you release the pressure at quick enough rate, so neutrons are allowed to separate before some of them decay into protons and be able to fuse another neutrons, you will get exactly the Big Bang result - Hydrogen, some Helium, a minor amount of Lithium and even less of everything else.

If you are slow, you will get heavier and heavier nuclei along the "neutron drip line" as in the stellar r-process. You are free to use them hot or wait them to decay into more stable elements.

Needless to say, both strategies require a great deal of energy - you will in essence need to revert the whole stellar evolution (milions of years of star radiative output) as well as the supernova explosion that created the neutron star in the first place.

Happy cranking!


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