Cauchy-Schwarz inequality state that in any inner product space: ${\displaystyle \left|\left\langle \mathbf {u} ,\mathbf {v} \right\rangle \right|^{2}\leq \langle \mathbf {u} ,\mathbf {u} \rangle \cdot \langle \mathbf {v} ,\mathbf {v} \rangle}$ for any u,v.
In the special case of L2 space (the inner product space of function that we use in quantom mechanics) the inner product between two functions $f(x)$ and $g(x)$ is the integral :${\displaystyle \int _{\mathbb {R} ^{n}}f(x){\overline {g(x)}}\,dx}$ and it follows that Cauchy-Schwarz inequality in this case become: ${\displaystyle \left|\int _{\mathbb {R} ^{n}}f(x){\overline {g(x)}}\,dx\right|^{2}\leq \int _{\mathbb {R} ^{n}}|f(x)|^{2}\,dx\int _{\mathbb {R} ^{n}}|g(x)|^{2}\,dx.}$
In quantum mechanics, the expectation values of any measurable quantity (correspond to $I(t_1),I(t_2)$) is given by the integral $I_i=∫_{R^n}|I`(x,t_i)|dx$ when $I'$ is the operator of the measurable value $I$. Similarly, The measurable value $I(t_1)I(t_2)$ So when applying Cauchy-Schwarz inequality we get: $I(t_1)I(t_2)≤I(t_1)^2I(t_2)^2$.
The 2 factor though look suspicious. Can you provide more details about I operator?