There is one thing in Ohms law I am missing I think.
Lets say you have a simple circuit with a single resistor, $R$. We apply voltage $V_1$ to it, by Ohms law the current is $I_1=V_1/R$.
Now we increase the voltage to $V_2$, I am wondering what actually happens then. Voltage is defined as energy per charge, so we increase the energy we are giving the charges over $R$, I assume this materializes as a stronger electric field? So then we accelerate the electrons up to current $I_2=V_2/R$? But I am wonder why the current/speed of electrons don't increase further? My rationale is this:
With the voltage $V_1$ we had an electric field that was strong enough to overcome the internal resistance and keep the current at $I_1$. I look at the internal resistance as a friction force $r$ on the electrons, and the work the internal resistance does is $rl$ where $l$ is the length of the resistor. When we increase the voltage to $V_2$ we also increase the force on the electrons, but the internal resistance is the same? So then the electrons should keep accelerating and the current should just increase and not find stop at $I_2=V_2/R$, because the other work on the electrons has increased, but the internal resistance and the friction work done by the resistor is the same? We keep feeding the electrons more and more energy?
Can you please explain the flaw in my argument and why the current doesn't just keep increasing?