Forces in a redirected rope where both strands are loaded So, if I take a rope, 'fold' it over something to redirect it and then load both strands in the same direction with a certain force, each Strand of the rope should See 50% of the tension, right?
But what happens at the 'top' of the bend, where both strands 'meet'? Do the forces there add up, so that the rope still sees 100% of the tension at one particular point?
I'm wondering because logically thinking (and in practice) a doubled rope holds double the strength of a the single Strand before breaking. I just dont quite get why, because there seems to be a point where both Split up forces seem to meet.
I'm probably over complicating this Problem, but it just doesnt go in my head somehow.
Any help is welcome!

 A: 
So, if I take a rope, 'fold' it over something to redirect it and then
load both strands in the same direction with a certain force, each
Strand of the rope should See 50% of the tension, right?

Each strand would see 50% of the tension that would have been if a single strand was used. So, tension in each strand would be F/2 where F is the weight / force pulling down on the entire thing.

But what happens at the 'top' of the bend, where both strands 'meet'?
Do the forces there add up, so that the rope still sees 100% of the
tension at one particular point?

At the point, where you have circled, if you draw a free body diagram, then there will be a force ( i.e. rope tension ) puling to the right of F/2 and a force ( i.e. rope tension ) pulling to the left of F/2 .
That is what we mean when we say , there is some tension in the rope. We mean, that each point in the rope is being pulled left and right by the same force and hence is in equilibrium
A: Assuming both strands hold a common load in equilibrium  (no sliding of the rope over the top "peg"), and assuming a massless rope, the tension in the rope is the same at every cross section of the rope, equal to half the tension for the single strand case.  There is a constraining force from the "peg" upward on the rope looped around it equal to $2T$ where $T$ is the tension in each strand.
