The elastic proton-antiproton $(p \bar p)$ scattering is a crossing symmetric process of elastic proton-proton $(pp)$ scattering. It is known from Regge theory that the elastic $pp$ and $p\bar p$ scattering amplitudes are the sums of $C$-parity $=+1$ and $C$-parity$=-1$ components:

$$A_{pp} = A_{+} + (-A_{-})$$

$$A_{p\bar p} = A_{+} + A_{-}$$

where $A_{+}$ denotes the $C$-parity $=+1$ component and $A_{-}$ denotes the $C$-parity $=-1$ component. The $C$-parity $=-1$ component has different signs for $pp$ and $p\bar p$ scatterings. This way the $C$-parity $=-1$ term results in a difference between the $pp$ and $p\bar p$ scattering cross-sections. Does this difference lead to the violation of crossing symmetry? Why? Or why not?


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.