I think also that the equation are not correct or misspelling ?
first I write the "rocket" equations for translation and analog for rotation, then the equations of motion in body fixed system.
the index r stay for rocket, the index f for fuel.
\begin{align*}
&\textbf{Translation }\\
\boldsymbol{p}_t&=(m_r+dm_f)\,\boldsymbol{v}\\
\boldsymbol{p}_{t+dt}&=m_r(\boldsymbol{v}+d\boldsymbol{v})+dm_f\,(\boldsymbol{v}+d\boldsymbol{v}+\boldsymbol{v}_{\text{rel}})\\
\boldsymbol{F}&=\frac{\boldsymbol{p}_{t+dt}-\boldsymbol{p}_t}{dt}=
\frac{m_r(\boldsymbol{v}+d\boldsymbol{v})+dm_f\,(\boldsymbol{v}+d\boldsymbol{v}+\boldsymbol{v}_{\text{rel}})
-(m_r+dm_f)\,\boldsymbol{v}}{dt}\\&=m_r\,\frac{d\boldsymbol{v}}{dt}+\underbrace{
{\frac{dm_f\,d\boldsymbol{v}}{dt}}}_{=0}
+\frac{dm_f}{dt}\,\boldsymbol{v}_{\text{rel}}\\
&\text{with:}\\
dm_f&=-dm_r\\\\
&\Rightarrow\\
\boldsymbol{F}&=m_r\frac{d\boldsymbol{v}}{dt}-\frac{dm_r}{dt}\,\boldsymbol{v}_{\text{rel}}\\\\
&\textbf{Rotation }\\
\boldsymbol{L}_t&=(\boldsymbol{I}_r+d\boldsymbol{I}_f)\,\boldsymbol{\omega}\\
\boldsymbol{L}_{t+dt}&=\boldsymbol{I}_r(\boldsymbol{\omega}+d\boldsymbol{\omega})+d\boldsymbol{I}_f\,(\boldsymbol{\omega}+d\boldsymbol{\omega}+\boldsymbol{\omega}_{\text{rel}})\\
\boldsymbol{M}&=\frac{\boldsymbol{L}_{t+dt}-\boldsymbol{L}_t}{dt}=
\frac{\boldsymbol{I}_r(\boldsymbol{\omega}+d\boldsymbol{\omega})+d\boldsymbol{I}_f\,(\boldsymbol{\omega}+d\boldsymbol{\omega}+\boldsymbol{\omega}_{\text{rel}})
-(\boldsymbol{I}_r+d\boldsymbol{I}_f)\,\boldsymbol{\omega}}{dt}\\&=\boldsymbol{I}_r\,\frac{d\boldsymbol{\omega}}{dt}+\underbrace{
{\frac{d\boldsymbol{I}_f\,d\boldsymbol{\omega}}{dt}}}_{=0}
+\frac{d\boldsymbol{I}_f}{dt}\,\boldsymbol{\omega}_{\text{rel}}\\
&\text{with:}\\
d\boldsymbol{I}_f&=-d\boldsymbol{I}_r\\\\
&\Rightarrow\\
\boldsymbol{M}&=\boldsymbol{I}_r\frac{d\boldsymbol{\omega}}{dt}-
\frac{d\boldsymbol{I}_f}{dt}\,\boldsymbol{\omega}_{\text{rel}}\\\\
\end{align*}
\begin{align*}
&\textbf{The equations of motion in body fixed coordinate system}\\\\
&\textbf{Translation}\\
\boldsymbol{F}&=m\left(\frac{d\boldsymbol{v}}{d\tau}+\boldsymbol{\omega}\times\,\boldsymbol{v}\right)-
\frac{dm}{d\tau}\,\boldsymbol{v}_{\text{rel}}\\\\
&\textbf{Rotation}\\
\boldsymbol{M}&=\boldsymbol{I}\frac{d\boldsymbol{\omega}}{d\tau}
+\boldsymbol{\omega}\times (\boldsymbol{I}\,\boldsymbol{\omega})-
\frac{d\boldsymbol{I}}{d\tau}\,\boldsymbol{\omega}_{\text{rel}}
\end{align*}
\begin{align*}
\\\\\\
&\textbf{Euler angle}\\
&\textbf{rotation matrix}\\
&\boldsymbol S=S_z(\psi)\,S_x(\theta)\,S_z(\phi)\\
&\Rightarrow\\
&\boldsymbol \omega= \left[ \begin {array}{ccc} 0&\cos \left( \phi \right) &\sin \left(
\theta \right) \sin \left( \phi \right) \\ 0&-\sin
\left( \phi \right) &\sin \left( \theta \right) \cos \left( \phi
\right) \\ 1&0&\cos \left( \theta \right)
\end {array} \right]
\,\dot{\boldsymbol{\varphi}}\\
&\dot{\boldsymbol{\varphi}}=\left[ \begin {array}{ccc} -{\frac {\cos \left( \theta \right) \sin
\left( \phi \right) }{\sin \left( \theta \right) }}&-{\frac {\cos
\left( \theta \right) \cos \left( \phi \right) }{\sin \left( \theta
\right) }}&1\\ \cos \left( \phi \right) &-\sin
\left( \phi \right) &0\\ {\frac {\sin \left( \phi
\right) }{\sin \left( \theta \right) }}&{\frac {\cos \left( \phi
\right) }{\sin \left( \theta \right) }}&0\end {array} \right]
\boldsymbol{\omega}
\end{align*}