Does entropy alter the probability of independent events? So I have taken an introductory level quantum physics and am currently taking an introductory level probability class. Then this simple scenario came up:

Given a fair coin that has been tossed 100 times, each time landing heads, would it be more likely that that the next coin flip be tails or heads?

I can see that since the event is independent by definition, then the probability would be even for both heads and tails:
$$P(h | 100 h) = P(t | 100 h)$$
But would this differ in a  quantum mechanical standpoint? I have a feeling that $P(h | 100 h) < P(t | 100 h)$ because of the push towards equilibrium in the entropy of the system. Am I wrong to think this way?

FOLLOW UP: (turning out to  be more of a statistical problem possibly?)
Something the around the "equilibrium only exists in the infinite-time limit" idea is what I'm getting hitched on.
The proportion of head to tails is 1 to 1 as number of trails approach infinity (this is a fact correct?). Therefore, if this must be the case, mustn't there be an enacting "force" per say that causes this state of being to (admitted unreachable, but technically eventual) case? Or is this thought process just illegitimate simple because the state exist on at the infinity case?
 A: As you mention in your question, this is the definition of an independent event. If the coin is indeed fair, then it is irrelevant what has happened in the past in order to determine the probability of future events.
This does not change in quantum mechanics. In fact, QM gives us the first concept of truly random events. As an explicit example of a quantum mechanical coin flip, consider the probability of a spin 1/2 particle being measured to have spin $|{+z}\rangle$, immediately after it was measured to have spin $|{+x}\rangle$: as you know, the probability is exactly 50%.
Regarding any "push towards equilibrium" due to entropy: thermodynamically, the free energy of the system is a property of the state of the system in equilibrium, which by definition has no concept of 'memory', whereas equilibrium only exists in the infinite-time limit. Thus, there can be no thermodynamic forces in response to a series of events that occurred in the past, if those events cannot be inferred from viewing a snapshot of the system in its current state.
The probability of a fair coin toss is always 50%, regardless of how many times 'heads' or 'tails' has been flipped in a row. Otherwise, one would be able to 'charge up' dice, or coins, or decks of cards: Let us roll dice all day, and wait for one of them to roll '1' many times in a row. Then, we'll go play dice for money.
A: The physics aspect of your question is answered by saying that quantum mechanics doesn't change anything in this situation. The conclusions you get from basic statistics continue to be valid.
Now, as for why that is:

I have a feeling that: $P(h | 100 h) < P(t | 100 h)$ because of the push towards equilibrium in the entropy of the system. Am I wrong to think this way?

Yes, you are wrong to think that way. Here's how that "push towards equilibrium" comes from: let's say you've flipped the coin 100 times and you have gotten 100 heads. That's a very drastic difference between heads and tails. Then you go on to flip the coin a thousand more times. You're most likely to get around 500 more heads and 500 more tails, for a total outcome of 600 heads and 500 tails. That's a much less drastic difference. Even with a 50-50 split between heads and tails, you will be closer to the equilibrium result of 550 heads and 550 tails because the 100-head excess is a smaller fraction of the 1100 total throws.
You can go on to flip a million more coins, and you're most likely to get 500000 of each heads and tails, for a total of 500600 heads and 500500 tails. Here the 100-head excess is barely noticeable relative to the total of 1001100 throws. As you continue to make more and more throws, that 100-head excess gets more and more negligible, even though all additional throws are equally likely to have either outcome.
A: The other answers are good, I just thought this would be a cute opportunity to learn some animation techniques in Mathematica. I start with a hundred heads and make a number of additional, fair, independent tosses. Then I compute the total fraction of heads and repeat this a thousand times and make a histogram of the results. This makes a single frame of the animation. As the number of additional tosses is increased you'll see the probability distribution for the number of heads shift towards $1/2$ and become more sharply peaked.
Hopefully this embeds okay (its only a 289 kb file):

A: This is a matter of QUALITY and aging  of the "fair" coins (long-aged one can be researched for instance in museums), the entropy will grow because of friction, the process of aging, bluring and deleting of signs i.e. tails/heads will continue during very long tossing, the coin has limited life which is usually not mentioned in ideal models. The question is if it is possible to recover the coin from pieces and if yes how count the entropy? About assembling small parts search-for: ribosome, or Maxwell's demon.  
