# Why can I see my face in a spoon?

If I hold a spoon with the concave side facing me, it approximates a concave mirror.

If my eye is symbolised with an arrow, then we can represent the situation like this:

The problem then arises. The image clearly forms below the eye and the rays all spread out below the median line, whereas my poor eye is above the line - so I shouldn't see any image.

I can however see my face when I do this with a spoon (very ridiculous to see grown man doing this). I do admit that there is one ray that I should be able to see:

However, is this singular ray able the only reason I can see my face or is there something else I'm missing?

• my poor eye is above the line - so I shouldn't see any image Why do you think that? The fact your eye is above the axis does not imply you cannot see the image. It's not clear what you are misunderstanding. is this singular ray able the only reason I can see my face? What do you mean? Are you asking if the whole image is contained in that one ray? – joseph h Feb 1 at 2:33
• Isn't that always how it works? For one eye to see one point of an image, there's usually just one ray that does it. For example, to see your nose in a mirror, you need the ray that leaves your nose going upward, just the right amount so it bounces off the mirror into your eye. – knzhou Feb 1 at 4:01
• No, your eye is symbolised with the crosshairs where the arrow meets the centre line. Your face is symbolised by the arrow. (Or more accurately, one half of your face; the other half of your face would be a corresponding arrow below the centre line.) – Graham Feb 2 at 15:28

Just to clarify, for you to see anything clearly at all, you do need multiple light rays traveling at multiple angles, hitting your eye lens at different points. Your eye lens focuses all these rays to a point on the retina, where their intensities add together to form a signal your retina registers.

And with the spoon example, this is exactly what happens! Let's review the steps.

1. Light bounces off of a point of your face. Because light rays come in from different angles, and your face is bumpy, these light rays scatter in all directions.
2. Some of the light rays bouncing off of that point of your face go in the direction of the spoon. These rays hit the spoon at multiple points and reflect off of the spoon.
3. Because the spoon is shiny and concave, it acts as a concave mirror, and focuses those reflected rays through a point in space somewhere between you and the spoon. This point is the real image formed by the spoon.
4. The real image acts as a new source of light which your eye can "focus onto": some of the light rays leaving this real image hit the lens of your eye, at multiple points of the lens, and are focused down to a single point on your retina.

To get a good understanding of how you (or a camera) can see something, it is often helpful to include your eye lens (camera lens) and retina (sensor plane) in the ray diagram. I've drawn such a diagram below that illustrates the steps above.

EDIT: Looking at Ryan's answer, I see your main confusion might have just been the arrow directions. But even in your model in which the pupil is a single point, it is good to remember you still should think of each "ray" that passes through the pupil as really a bundle of rays that can diverge or converge as it travels through space.

• Very intesting! I think part of my confusion comes from step 3. If the image forms there, why does it look like the image is from the surface of the spoon and not floating in mid - air? – John Hon Feb 1 at 14:02
• I think that our visual perception of it being on the spoon has to do with the distortions that the spoon provides, the coloration the spoon imparts, and that the edges of the spoon occludes the rest of the image that would otherwise be reflected. Also, as you move the spoon, the image size changes in a way distinguishable from a real object. As humans, we get used to these visual indicators that something is a reflection, just as you know there is not a clone on the other side of a mirror. – Jonathan Jeffrey Feb 1 at 14:21
• But, to be clear, it really does act much like a floating image. If you want to do a bit of an experiment, you could set up a camera with a shallow depth of focus pointing at a concave mirror forming a real image.You'll find you can focus on the real image, leaving the spoon blurry, and it will very much look like an image floating in space. You then increase the focal distance to focus on the spoon. – Jonathan Jeffrey Feb 1 at 14:29
• @JohnHon It's just because the image and your spoon are pretty close anyway, so you can't really tell the difference. It's completely possible to make an optical setup where the image is displaced enough from the mirror to look like it's floating in midair, such as in this toy. – knzhou Feb 2 at 3:59
• I think I get it now. There is a real image made for EVERY point of my face and they all float in the air. I can only see these real images because the real image projects light radially into my eyes. I think my main problem was I forgot that lines that DO NOT pass through the focus existed! Also, you don't need every ray that forms the real image to go into your eye to see the image - just some is fine. I also forgot that the eye is not a point! Thank you for your detailed response! Love from Aus – John Hon Feb 3 at 4:16

The rays you drew only represent the image of the top of the arrow. If you wanted to know how you can see each part of your face, you would need to draw all the rays that corresponded to the different parts of your face, bouncing off the spoon and returning to the top of the arrow (assuming that's your eye). A very rough sketch...

So you see your face, upside-down, and you see it at the location of your eye.

• This is really enlightening! However, how would you fit this in with the real image formed? Most of the rays you've drawn don't touch the real image in the way my red line did – John Hon Feb 1 at 14:20
• Remember, each "ray" here is actual a bundle of rays that are focused to form real images at different heights from the optical axis. It is not shown here, but there is a vertical (somewhat) plane where all of those real image points line up. – Jonathan Jeffrey Feb 1 at 16:14
• In the image the reflections don't follow the reflection rule that the angle of the incoming ray is the same as the one of outcoming ray. I know it is supposed to be a schematic picture, but it's extremely bad. – user1079505 Feb 1 at 16:46
• @JohnHon, yes, what Jonathan Jeffrey said - for any given point on the object, there is a plane in which all the rays from that point will intersect again - that's where the real image is formed. – levitopher Feb 2 at 14:28
• @user1079505 I hear you - if you added normal vectors to my curved surface, you would see that incidence angles do not really match reflection angles. But really, I did this using Noteability, and was mostly trying to deliver the perspective that your eye is seeing many different parts of the object. I think I made that point, bad drawing aside. – levitopher Feb 2 at 14:30

That singular ray is only how your eye sees your pupil. The other parts of the image will come from the other rays. For instance the top ray might be going to your chin, which is why you look upside down. To think of it this way you should really draw the arrows with their heads on the other ends, since they give the paths of rays that you see.

# Black Hole

We are taught in school that a curved mirror/lens will form an image at the focal point. However, there are an infinite number of points which are not the focal point which also produce some image. They just don't produce the expected image! So the question is: if you move your detector (eyeball, film, CCD, etc.) around the field near the focal point, can you find a spot where no light rays appear? Can you find a "black hole" where you look at the spoon, but there is no spoon? Of course you cannot.

# Flat Mirror

If we consider a typical bathroom/bedroom mirror, we can ask: where is the focal point? And the answer is: everywhere. That's because it reflects the rays with 0 curvature, so there is no "focusing" effect. No matter where you stand in front of a flat mirror, you will see a "clear" image. Hopefully, this is not surprising or controversial.

# Convex Mirror

Now consider the convex mirrors placed in corners to enable pedestrians or drivers to see around a corner. Again, we can ask: "Where is the focal point?" And again, the answer is: "everywhere in front of the mirror". The main difference between a flat and a convex mirror is that a flat mirror will show you a field which is the same size as your visual field without the mirror present (your viewing frustum is the same size, but oriented backwards in space), but the convex mirror will show you a wider field (the viewing frustum is larger, because the mirror collects rays that you would not otherwise see and sends them to your eyeballs). Now, this is strange! How can we see more than we can see? If a flat mirror lets us see our full field of view, then how can a convex mirror show us more than the full field of view? And it does so by distorting the image. It squeezes the portion you would normally see in order to make room for the additional image. Even so, moving about in front of the mirror will not reveal a "black hole" where no reflected rays are sent. An image is formed at every point in front of the mirror (though it's a different image for every point).

# Concave Mirror

Finally, we arrive at the concave mirror. It might seem like it's very different from the convex or flat mirror, but it is not. In fact, it works very much like a convex mirror. Note that parallel rays hitting a flat mirror produce parallel rays upon reflection, which is why the image formed by a flat mirror is not distorted (except for the 3D inside-out inversion, but that's a different topic). Convex mirrors reflect parallel rays into diverging rays, causing distortion. And obviously, concave mirrors reflect parallel rays into converging rays, producing our desired focal point.

So what do we see if we are not at the focal point? Well, that depends on where we are! If we are "in front of" the focal point (meaning, between the focal point and the mirror), the rays are still converging, and so we will see the same image orientation as a flat mirror, but enlarged, because we are collecting light rays from a broader field. However, this enlarged image will only be a subset of the field that the full spoon can reflect.

On the other hand, if you are "behind" the focal point, then the rays will converge onto the focal point, and then continue on their merry way, diverging from each other. In this region, the concave mirror acts somewhat like a convex mirror, with an additional directional reversal! That's why moving the spoon further away from you allows you to see a broader field of view, just like a convex mirror would. In particular, the rays which converge on the focal point don't stop there just because that's where we normally put a camera sensor. They keep on going, spreading out and forming a shrinking image (because of their divergence) which just keeps getting smaller the further you go from the spoon. But the fact that they all converged on the focal point means they will all cross at that point and invert the image beyond.

I can however see my face when I do this with a spoon (very ridiculous to see grown man doing this). I do admit that there is one ray that I should be able to see:

Your diagram assumes that your eye is a single point. Yes, if we take the perspective that we have a vanishingly tiny, single-point camera, then since that camera can intercept only one ray, that one ray is how it can capture its own reflection. Every other ray emanating from the camera, and bouncing off the mirror misses that vanishingly tiny camera.

If you want to understand why you can see your face, you need a more robust diagram which models points on your entire face, in relation to the concave mirror and the eye, and which also has a model of the eye that is not a single point, but a lens that captures multiple rays from the same point source.