Why does the 3-point function of a real scalar field vanish? $$\langle0\lvert T\hat\phi(x_1)\hat\phi(x_2)\hat\phi(x_3)\rvert0\rangle$$
I'm looking for an intuition to it, if not an actual interpretation. Otherwise, I know how to get the result 0 using Wick's theorem. The same question applies to any n-point function with odd n.
 A: You have not specified what theory you are working with, but I am assuming you are working with free scalar field theory (possibly including a $\phi^4$ interaction term).
Intuition is a bit hard to define, but perhaps the easiest way to see this is that your Lagrangian is invariant under $\phi\rightarrow -\phi$  (a $\mathbb{Z}_2$ symmetry), so the field $\phi$ and the field $-\phi$ are physically indistinguishable.
Thus, any product which includes an odd number of fields must vanish.
The three-point function can be interpreted as "starting from vacuum, what's the probability of creating three particles and ending up back in the vacuum?". If your particles have charge, then you cannot create an odd number of them whilst conserving charge.  Here the charge is a $\mathbb{Z}_2$ quantity rather than a U(1) electric charge (as it would be in e.g. complex scalar field theory), which may be a bit harder for intuition but the math works the same way.
A: Because you average over a state with a definite number of particles, while the field operator changes the number of particles by 1. This is of course specific to how youd efine the averaging (i.e., your ground state in this case) and the field operators. Superconductivity and superfluidity are the examples where the ground state does not have a finite number of particles, so odd averages like $\langle\phi(x)\rangle$ do not necessarily vanish.
