# Why are there two pressures acting on a body in opposite direction during free fall on earth?

This is how my sir explained this to me:

There are more than billions of atoms present in the earth's atmosphere. All those atoms have their force acting downwards.

When he explained this diagram to us, he said that pressure is a perpendicular force. So it also acts in upwards direction. I am not able to understand this. If all forces are acting downwards, how come atmospheric pressure in acting upwards as well as downwards?

I did not draw in the image another direction of pressure acting upwards from below because that was not the image in my mind but the one that I have drawn is.

I also agree with the point that gravity will also keep on decreasing as we go higher and higher.

My answer to this is that (please correct me if I am wrong):

If a body is going down, it exerts a force of its weight on air, therefore air exerts an equal and opposite force on it. But it is wrong since it should be a value of 1 atm and not the weight of the body.

Then, from top we can say that there is a force acting downwards on the body which is pushing it downwards and that is atmospheric pressure.

• In what sense are all the forces downwards? If that were so, all the air molecules would fall down and lie on the surface of the earth! Commented Dec 26, 2020 at 13:38
• @mikestone Yes.That is why Commented Dec 26, 2020 at 13:38
• Can’t we say that it is like there are just too many of those atoms, Commented Dec 26, 2020 at 13:39
• That it is like filled inside that atmosphere Commented Dec 26, 2020 at 13:39
• Now@mikestone I am also not able to relate it with the question that I have. Commented Dec 26, 2020 at 13:40

I did not draw in the image another direction of pressure acting upwards from below because that was not the image in my mind but the one that I have drawn is.

Your image in your mind is that pressure is a force which does not act upwards. That means that an object will experience an unbalanced downward force due to the atmospheric pressure of $$14\text{ psi}$$. This force will depend on the amount of surface area that is pointing upward. The more upward surface area the greater the pressure.

A simple experimental disproof of your theory is rather easy. Hold your hand flat with the palm facing upwards and the fingers together. Now, rotate your hand so that the palm is sideways. By doing so, you changed the upward surface area from about $$35\text{ in}^2$$ to about $$5\text{ in}^2$$. If your theory is correct there would be a difference in $$30\text{ in}^2 \ 14\text{ psi}=420 \text{ lb}$$ downward force. Since you do not feel that dramatic increase in force then you can be sure that the pressure does act upwards as well.

As a further exercise, consider also the forces exerted on a helium balloon. Could a helium balloon float if it were only pushed down with air pressure as you describe? Estimate the forces acting on the balloon according to your theory.

If a body is going down , it exerts a force of its weight on air , therefore air exerts an equal and opposite force on it.

You do have Newton’s 3rd law correct here, but not the magnitude of the force. The weight is a gravitational interaction between the object and the earth, it is not the air pressure. Since the object is moving the interaction with the air can be split into two parts: the buoyant force and the drag force. The buoyant force is the difference in the static pressure from the top to the bottom of the object. It is equal to the weight of the displaced air, not the weight of the object. The drag force is largely due to friction. As an object falls down, both of these forces point up. A balloon uses the buoyant force to float and a parachute uses the drag force to fall slowly.

• Could you please elaborate or simply it a bit more ? I did not understand the point where you said that you do not feel that dramatic pressure. Commented Dec 27, 2020 at 5:59
• @user102532 I have added an explanatory paragraph. Basically, it is very easy to experimentally show that pressure does not behave the way you drew.
– Dale
Commented Dec 27, 2020 at 12:41

Atmospheric pressure comes from air molecules bouncing of the object. As the molecues are moving in random directions, the average force they exert is perpendicular to the surface they are hitting. The total force on an object at rest in the air is therefore it's weight together with the sum of the pressure forces. This sum is called buoyancy, and is equal to the weight of the air which would be present if the object were not there. We know this is so because, left to itself, the air does not fall down. Once the object starts to fall then there is also air resistance, but there is no simple formula for air resistnce,

• The question is that only, why is it that the molecules exert a force perpendicular to surface.Is it a result of action reaction pair ? Let us say a body is going down , then it exerts a force on the air molecules and in return , air molecules also exert an equal and opposite force on the molecules.The Main point is the reason for pressure to be always perpendicular to the surface. Why ? Commented Dec 27, 2020 at 6:01

The atmospheric pressure — as the hydrostatic pressure — is caused by gravity, particularly by weight of the air above a given point.

So someone my imagine it like this (gravity is nevertheless downward force, isn't it?): But it is not correct.

Atmospheric pressure works in all directions, so more realistic picture is like this one: Now let's put a body between those different altitudes and we may see that the upward pressure on the body not only exists, but it is even larger than the downward one.

But wait a moment... how gravity with its downward direction may cause an upward force?

• ### And what does gravity with a stone falling into water? It pushes some water upward.

Here are some other examples of how gravity pushes things upward: