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I'm writing a game prototype with simple 2D Physics, of a 2D rocket "lander" style.

Let's assume that there is a downward gravity of (0, -1).

The rocket has an up-vector (that can be also described as an angle) and it generates a thrust of e = -2g from its "down" vector; From a simple formula:

v = (u * e) + g 

I'm able to predict the resulting 2d velocity when the Rocket is pointing upward to u vector. For example, if the rocket is pointing up (90 degree, normalized vector (0, 1)):

v = ((0, 1) * 2) + (0, -1) 
v = 0,1 (rocket lifts with 1g force and no movement in x, as expected) 

Now, for a 30 degree inclination:

v = ((0.87, 0.5) * 2) + (0, -1) v = (1.74, 0)  

At this angle, the rocket finds a balance between gravity and its thrust moving only sideways. This is also verifiable by assuming that to keep movement y = 0 the resulting y component of thrust vector should cancel gravity (for e = 2g, it should be 0.5) So the angle should have a Sine of 0.5, then

arcsin(0.5) = 30 degrees

The question is, I want to be able to find the correct up vector to give the rocket an arbitrary v resulting velocity (to reach any target in 2d space). If we rearrange the formula:

u = (v - g) / e 

The Problem is, to this work I should input vector v in correct length and I don't have it. I have just a direction to the target, normalized.

In the above example, 30 degrees should be the result if I was asking for 0 degrees (right vector) resulting velocity. But I would input v as (1, 0) and not (1.74, 0).

I'm sure I'm missing something very very basic but right now my mind can't unwrap it.

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  • $\begingroup$ I think what you are asking is really a math question. Can you provide with a sketch of the thrust vectors and other important things. $\endgroup$
    – JAlex
    Dec 11 '20 at 19:44
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Your calculations are correct, but the problem is that if the angle of the vector $u$ is the only thing you can change then you cannot have control on both the angle and the magnitude of the output $v$: they will not be independent. So as long as the thrust $e$ is fixed you cannot have $v=(1,0)$, whichever the angle is.

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