Is a heavier skier faster? Is it true that a heavier skier goes faster? If it is, why is that?
My intuition would be that the speed gained by a skier should be independent from its mass, since both its acceleration and the friction are proportional to its mass. Am I overlooking some important effect which would cause a heavier skier to go faster?
 A: I'm quite sure that you've left something. The more their mass, they've got more momentum and of course, Inertia. The heavier the body is, the more their body resists their state of motion (or rest).

Yes. They move faster than skinny guys. If you resolve the forces acting on the skier like his acceleration, gravity, friction (of snow), the normal force and also his air drag, you can find that his velocity does depend on his mass.
Resolving all the forces, we get
$$ma=mg\ cos\theta-\mu\ mg\ sin\theta-\frac{1}{2}\rho Av^2C_d$$
$$a+\frac{1}{2m}\rho Av^2C_d=g\ cos\theta-\mu\ g\ sin\theta$$
As the mass is in the denominator portion, we can clearly see that it supports his acceleration (it should increase in order for balancing other forces) by opposing gravity.
A: The skier has the following forces acting on him:


*

*a normal force $F_N$

*a gravitational force $F_W=mg$

*a force from air friction that is probably well approximated as $F_a=cAv^2$, where $A$ is the skier's cross-sectional area

*a frictional force from the snow $F_f$


$F_a$ increases with speed, and $F_f$ may also have some velocity dependence as well, and this is why a terminal velocity exists. The terminal velocity is the one at which the vector sum of these forces is zero.
If $F_f$ is negligible, then clearly a heavier skier will have a greater $v$, because we need a bigger $F_a$ to cancel out the component of $F_W$ parallel to the slope.
If $F_f$ obeys the usual freshman-physics model of kinetic friction, then it's velocity-independent, and a simple calculation shows that the same conclusion holds for fixed $A$: a heavier skier goes faster. In reality, a bigger skier has a bigger $A$ as well. However, I don't think the qualitative result is altered, because under geometrical scaling, $m$ grows faster than $A$.
However, I don't think it's necessarily valid to assume that $F_f$ obeys the usual model of kinetic friction, which is usually found to be valid only when a solid, dry surface slides over another solid, dry surface. Here the skier is leaving a track by pushing aside the snow (unless the conditions are very icy). I would guess that something like $F_f\propto F_N v$ holds. If this form of $F_f$ applies and $F_a$ is absent, then all forces are proportional to mass, and the terminal velocity is independent of mass. If this form of $F_f$ exists along with an $F_a$, then I think you'd come back to the same result, which is that heavier skiers would go faster.
But the whole thing really depends on the model of friction, and I don't think any one model of friction will be accurate for a variety of conditions (ice, deep powder, ...).
