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The structure has helicities on two levels and looks like the tungsten wire in an incandescent light bulb:

enter image description here

How, if at all, can the spring constant be derived from elastic properties of the material, the pitch of the two helicies and the three radii of the structure? The ends of the structure can only move in the direction of the axis of the largest helix and have otherwise fixed clamping.

The reason for engaging with this odd geometry is to easily investigate situations where there is an excess of tunable properties. I want to find an easily workable mechanical stress situation similar to electrodynamical Maxwell stress in Lorenz gauge where two different kind of stresses balance each other and yet allow for change of some combination of properties. In a mechanical situation this could lead to the very effectful situation of elastic deformation without force. Specifically two parameters can be set in the clamping: the torsion of the two helicies. Are there maybe clampings allowing for a spring constant of zero?

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  • $\begingroup$ Where are you getting the idea that a different elastic modulus is needed to describe each degree of freedom? All linear elastic behavior can be described by any two of the Young's elastic modulus, Poisson ratio, shear modulus, and bulk modulus. Only two of these can be independent. $\endgroup$ Commented Dec 1, 2020 at 22:35
  • $\begingroup$ Minor correction: all linear elastic behavior of an isotropic material can be described as you said. But unless there was some complicated manufacturing process involved, you answer looks good IMO. $\endgroup$
    – alephzero
    Commented Dec 2, 2020 at 1:17
  • $\begingroup$ Is there still something wrong with this question? $\endgroup$ Commented Dec 8, 2020 at 2:43
  • $\begingroup$ I don't understand what is wrong with this question. Sometimes a motivation is needed, sometimes not. Stack Exchange is very heterogeneous on that. Since you haven't opened the question I will add a motivation for my question. $\endgroup$ Commented Dec 11, 2020 at 14:38
  • $\begingroup$ Now I have reunderstood the situation to the opposite. If you now fail to open the question then you have not acted in alignment with the rules of Stack Exchange. $\endgroup$ Commented Dec 11, 2020 at 15:02

2 Answers 2

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I assume you're asking about compression or elongation of this structure along the primary helical axis.

Let's first look at the standard helical spring model, which translates axial spring deflection into torsion of the bulk material:

enter image description here

For simple torsion, the relationship between the twist angle $\theta$ and the torque $T$ for a circular cross section of radius $r$ is

$$\theta=\frac{2Tl}{\pi G r^4}$$

where $G$ is the shear modulus and $l$ is the length of the rod. This model forms the basis for the simplest calculations of the spring constant of a helical spring, as the torque $T$ is coupled to the end load $P$ by $T=PR$ (where $R$ is the radius of the helix, or half the width of the spring) and the rod length $l$ is coupled to the spring length $L$ by $L=2\pi NR$, where $N$ is the number of coils. We end up with a spring constant $k$ of approximately

$$k=\frac{P}{x}=\frac{Gr^4}{4NR^3},$$

where $x$ is the spring deflection.

Now, however, with the second level of helicity, compression involves torsion applied not to a circular cross section of bulk material but to the smaller helix. This now involves either elongating or compressing the bulk material, not shearing it. In other words, the problem can be transformed into uniaxial strain of a long, thin rod (or bar or wire), which depends only on the cross section and length (which can be calculated from the geometry) and on Young's modulus. Since twisting a helix by an angle $\theta$ gives end motion of $\theta r$ (for radius $r$), corresponding to axial deformation of the rod of length $2\pi n r$, where $n$ is the number of turns of the smaller helix, the required axial strain is

$$\varepsilon=\frac{\theta}{2\pi n}=\frac{F}{AE},$$

where $F=T/r$ is the axial force on the rod, $A$ is its cross-sectional area, and $E$ is Young's modulus. This corresponds to a modified spring constant $k^\prime$ of

$$k^\prime=\frac{AE}{2\pi n R}$$

for this extensional mode. Note that additional deformation modes also play a part; as described in the link above, the external load on the spring also induces bending of the helix, for example. This must be analyzed separately.

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I conjecture that only the shear modulus will be relevent. That is the case for twisting a rod, and I believe that that descends to the case of a single level of helix where stretching just twists the material. Some serious differential geometry will have to be done to see what twist arises from stretching your helical-helix structure though.

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  • $\begingroup$ I disagree; the addition of a second level of helicity results in uniaxial strain in the bulk material when the complete structure is compressed. Uniaxial stresses and strains in long, thin configurations are coupled solely by Young's modulus. Please see my answer. $\endgroup$ Commented Dec 1, 2020 at 23:16
  • $\begingroup$ @Chemomechanics Cool! $\endgroup$
    – mike stone
    Commented Dec 2, 2020 at 13:01
  • $\begingroup$ @mikestone Shear in what direction? How is this direction changed with the resulting strain from the shear? $\endgroup$ Commented Jan 5 at 15:20

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