# Why a fan make us feel colder instead of warmer in a cold room? [duplicate]

Stay in a cold closed room, turn on a fan directed at you, it makes you feel colder instead of warmer. why?

Here is the definition of heat:

Matter exists in different physical forms – solids, liquids, and gases. All matter is made of tiny particles called atoms, molecules, and ions. These tiny particles are always in motion – either bumping into each other or vibrating back and forth. It is the motion of particles that creates a form of energy called heat (or thermal) energy that is present in all matter...

so before turning on the fan, the air molecules are relatively still and not moving much. After turning on the fan, they are moving a lot faster so the motion of the particles is more and it should create heat, but why can't we feel the heat on our body and skin when standing in front of the fan? (at least in my experience)

• FWIW, stirring the air in a closed room does increase the temperature, and also, the fan's motor, which is less than 100% efficient will lose some heat into the air, but both of those effects are small compared the "cooling" that you will feel, as explained in the answers below. Nov 29 '20 at 20:55
• "Before the fan is turned on, the air molecules are relatively still". No sir, if the air molecules were still, you would be standing on a block of frozen air near absolute 0. Gaseous air molecules have a lot of motion, indeed, that degree of motion defines temperature. The energy imparted to the air by the fan is patheticly small. Noticable heating from motion generally occurs at speeds beyond the sound barrier. The Concorde or a re-enteting space capsule are good examples. Moving air taking heat away is "wind chill factor". Nov 30 '20 at 1:17
• Ah. My eyes! This definition of heat is horribly wrong. Heat is neither temperature nor internal energy. Please burn any book which contains this definition. Nov 30 '20 at 8:33
• Do not think of air flow as moving molecules in this context. When investigating the fluid flow it is normally much better to treat it like a continuum. You then avoid confusions like this one. If the room is a closed system, the kinetic energy of the continuum will ultimately be transferred to the internal energy (increasing the temperature) of the air and the walls by friction and viscosity, but it takes time. You only need molecules to describe the origin of viscosity, but after doing that you can and most often should ignore them. Nov 30 '20 at 10:20
• Nov 30 '20 at 10:48

First of all, that is not a definition of heat. Heat is energy transfer due solely to temperature difference. What is described in your post is more like a definition of internal energy (kinetic and potential energy at the microscopic level).

The reason you feel colder with the fan on is the movement of air over your skin increases the rate heat transfer from your skin by increasing the convection heat transfer coefficient. The relevant equation is Newton's law of cooling

$$\dot Q=hA(T_{s}-T_{∞})$$

Where $$\dot Q$$ is the heat transfer rate, $$T_s$$ is the skin temperature, $$T_∞$$ is the bulk air temperature of the air away from the skin, $$A$$ is the cross sectional area of the skin, and $$h$$ is the convective heat transfer coefficient. The faster the air moves the greater $$h$$ is, all other things being equal. In effect, the air movement forces the air close to the skin to carry heat away increasing the efficiency of heat transfer to from the skin to the air.

You've probably heard of the "wind chill factor". For a same air temperature the wind increases heat loss from the skin making the air feel colder than when there is no wind.

Thank you for the answer, that definitely helps, just one question, do we ignore the motion of air molecules due to fan movement because it's too small, negligible and fan is not rotating fast enough? or the fan moving the air in a cold room never creates any heat even in microscopic levels, no matter the speed of the fan?

Keep in mind the fan does not "create heat". Heat is energy transfer due to temperature difference. I think what you are really asking is if the fan can increase the temperature of the air molecules because the fan increases the velocities of the air molecules. It is possible that the fan could slightly, but not measurably, increase the temperature of the air by "stirring up" the air molecules, since the temperature of the air is a measure of the average translational kinetic energy of the air molecules. But the fan motor coil, which gets hot when the motor is running, would probably have a greater effect on the air temperature.

Hope this helps.

• Thank you for the answer, that definitely helps, just one question, do we ignore the motion of air molecules due to fan movement because it's too small, negligible and fan is not rotating fast enough? or the fan moving the air in a cold room never creates any heat even in microscopic levels, no matter the speed of the fan?
– Sam
Nov 29 '20 at 20:41
• @Sam I have updated my answer in response to your follow up comment. Nov 29 '20 at 21:00
• For higher velocities .. approaching Ma=1, the dynamic temperature "T = u²/2cp" is becomes more significant, and the difference between static temperature in the fluid and stagnation temperature is certainly measureable. Simple thermo-couple measurements (as in "thermocouple-wire stuck in the flow") show some temperature between he static and the stagnation temperature, because of heat conduction effects within the measurement probe. Nov 29 '20 at 21:23
• Where does the fan's power go, once it's all dissipated? and from a room-temperature perspective, where's the difference to heating the room using an electric heater of the same power? Nov 29 '20 at 21:25
• @towe see powerelectronictips.com/… Nov 30 '20 at 12:24

The still air near your skin has higher humidity that the air that the fan brings into contact with your skin; the drier air promotes evaporation of moisture from your skin. Your body provides the latent heat for this evaporation, hence you cool off.

After reading Bob D's answer, I would say both increased heat transfer from convection and evaporation are important. You can consider both effects by increasing the heat transfer coefficient in Bob D's formula to consider evaporation. (To be technically accurate, evaporation is mass transfer from the body to the air, not really heat transfer, but its effect can be lumped into the heat transfer coefficient. See, for example, the classic McAdams Heat Transmission textbook.)

– Sam
Nov 29 '20 at 21:04
• You are welcome. Nov 29 '20 at 21:05

In addition to the (by now) two great answers, what we perceive as heat/warm is in most common situations caused by random movement of the air molecules.

You are correct to think that the increased kinetic energy of the air molecules (caused by the fan) should transfer more energy to your skin, thus increasing the perceived temperature. As mentioned by Carl Berger, this is basically the same process that makes spaceships re-entering the earth's atmosphere heat up - there is relative motion between the object/observer and air particles in both cases.

However, as explained by John Darby, a uniform particle flow (which is caused by the fan or wind, for example, causes a chilling effect, thus cooling the perceived temperature.

If the particles move randomly (as in "normal" air without wind), the random movement of the individual molecules (approximately) cancels out and doesn't cause a windchill effect. They however still transfer energy to your skin, so increased movement will lead to a higher perceived temperature.

In summary, the increased uniform movement particle does transfer more energy to your skin, but the cooling effect that it causes is stronger, so in total, you feel a drop in perceived temperature. If there is no wind (random particle movement), the chilling effect doesn't happen, which means that higher particle movement equals higher perceived temperature.

• The temperature peceived is the temperature of the skin, and the windchill effects have been pointed out beforehand. The uniformity of the flow is not important, the temperature in the stagnation point increases by the extra kinetic energy due to the air flow velocity. For a living room fan that's very minor, for a supersonic aircraft it's certainly visible, and spacecraft during re-entry need to be protected against it, hence the heat-shields. Nov 29 '20 at 21:33
• @CarlBerger thank you for the clarification. I've edited my answer. It is hopefully better now. Nov 29 '20 at 22:17

Others have given wonderful answer. But I think one more point is necessary here.

Why does a wet cloth become dry when the wind is blowing ?

Actually if we take a closed beaker half filled with water and vacuum in the upper half then the upper half is not vacuum after sometimes. This is because some of the higher energy molecules in the water manage to break the influence of bonds and fills the vacuum area.

After some more time, the amount of water remaining in the lower half becomes fixed. So we say that the liquid water is with equilibrium with the vapour state.

Now coming back to your question, when the fan was switch off , the air near to your skin was in almost equilibrium with your skin but when the fan was switched on, it created an unbalance situation leading to decrease in pressure out and thus more liquid comes out from your skin for stability and by evaporating they take away energy and you feel cool.

Hope it helps 🙂.