If the total mass of a black hole were at the event horizon and not at the center of the black hole sphere, would that particles exchange gravity in directions tangential to the radius of the event horizon and try to squezze their position towards the center but which would not in any case affect the radius of the horizon?

  • $\begingroup$ What are you trying to ask? It's very unclear to me. Are you considering a Schw or a Kerr black hole? And what particles are you referring to??? $\endgroup$ Nov 29, 2020 at 14:26
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    $\begingroup$ Related: physics.stackexchange.com/questions/588429 $\endgroup$ Nov 29, 2020 at 14:30
  • $\begingroup$ Are you thinking of the shell theorem ? $\endgroup$ Nov 29, 2020 at 14:32
  • $\begingroup$ Also see physics.stackexchange.com/q/937/123208 I quite like Stan Liou's answer, especially: "Therefore, rather than gravity having a special property that enables it to cross the horizon, in a certain sense gravity can't cross the horizon, and it is that very property that forces gravity outside of it to remain the same." $\endgroup$
    – PM 2Ring
    Nov 29, 2020 at 14:52
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    $\begingroup$ Actually, it's probably better to avoid thinking of gravity as a force in GR. It's just spacetime curvature, so nothing needs to be transmitted. Take a look at this old Usenet Physics FAQ: How does the gravity get out of a black hole? $\endgroup$
    – PM 2Ring
    Nov 29, 2020 at 19:02


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