What would happen to capacitance and other quantities like Voltage if I initially take a Parallel Plate capacitor with each plate having equal charge "$q$" and then connect it to a constant voltage supply (battery)?
I know Capacitance is a geometrical quantity and the battery doesn't supply any net charge to capacitor plates. But if we go by this definition, we know that across the Capacitor plates, the voltage drop = EMF of battery (ignoring internal resistance) and if we go by the relation $Q = C\cdot V $ as $C$ and $V$ remain the same. The charge on each plate comes out to be $CV$.
Is the formula $C = Q\cdot V$ still applicable or not and what will the charge distribution be like?