0
$\begingroup$

In non-relativistic quantum mechanics, in position space, the complex conjugate operator $C$ flips the sign of the momentum operator, $CpC=-p$ (and thus also flips the sign of the orbital angular momentum).

The operator $T=C$ is usually called the time reversal operator, but this only works in certain cases. For example, it does not work in the presence of spins (where $T=Ci\sigma_y$). So $C$ may not always be called the (full) time reversal operator.

Would it be safe to say that $C$ is the momentum reversal operator? I think this holds always. Also, does $C$ do anything else that is not associated to momentum directly? Is the general behavior of $C$ well-studied? References would be much appreciated.

Edit: after writing this, I realized that it also flips the sign of $i\partial_t$ (some kind of energy reversal?), but I am not sure how helpful it can be to talk of non-stationary states (or of relativistic quantum mechanics).

Edit: I now realize that this question is ill defined, I did not want people to focus on the basis issue. A better question would be to ask specifically how to generalize the $C$ operator to other basis in relation to time and momentum.

$\endgroup$
2
  • $\begingroup$ What does "flip" mean here? $\endgroup$ Commented Nov 17, 2020 at 19:00
  • $\begingroup$ @N.Steinle to flip signs, $p\to -p$, for example. $\endgroup$
    – Mauricio
    Commented Nov 17, 2020 at 19:06

1 Answer 1

3
$\begingroup$

The "complex conjugation" operator is basis dependent and so ill defined.

A vector that has real components in one basis may be have complex components in another. For example the $x\leftrightarrow p$ change-of-basis formula for the components is $$ \tilde \psi(p) = \langle p|\psi\rangle = \int dx \langle p|x\rangle\langle x|\psi\rangle= \int dx e^{ipx}\psi(x) $$ and the $i$ in $e^{-ipx}$ means that a state $|\psi\rangle$ that has real components $\psi(x)=\langle x|\psi\rangle$ in the $|x\rangle$ basis can have complex components $\tilde \psi(p)=\langle p|\psi\rangle$ in the $|p\rangle$ basis.

Correspondingly the $\hat p$ opertor acts as $-i\partial _x$ in the $|x\rangle$ basis and so flips sign under congugation, while $\hat x$ which acts by multiplication by the real number $x$ does not. But in the $|p\rangle$ basis $\hat p$ is just multiplication by the real number $p$ while $\hat x$ acts as $i\partial_p$, so the "flips" are reversed.

As consequence of this, "complex conjugation" can only be defined as an operator if you also specify a set of basis vectors that are declared "real"

Thus, when defining antilinear operators such as time reversal it is dangerous to factor the operator as "$T=Ci\sigma_y$" -- although this is common practice. It is confusing because this formula is only correct when acting on states in the $\sigma_x$-diagonal or $\sigma_x$-diagonal bases which are connected by change-of-basis matrices with real entries. If you have need to use a different spin basis, say the general ${\bf n}\cdot {\boldsymbol \sigma}$-diagonal basis, the formula for $T$ is different.

$\endgroup$
3
  • $\begingroup$ Thanks for explaining the issue of the basis. Do you know if in the absence of spins, would a momentum reversal operator always be equivalent to the time reversal operator? $\endgroup$
    – Mauricio
    Commented Nov 27, 2020 at 14:04
  • $\begingroup$ Also see the last edit. $\endgroup$
    – Mauricio
    Commented Nov 27, 2020 at 14:30
  • $\begingroup$ Sorry for the long wait, I know realize that the key part is this antilinear property. $\endgroup$
    – Mauricio
    Commented Sep 22, 2021 at 17:05

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.