Question:In the arrangement shown in figure,the ends P and Q of an inextensible string move downwards with uniform speed u. Pulleys A and B are fixed. The mass M moves upwards with a speed-
Actual solution: Let the speed of mass M be v.The length of the string will remain constant. So by constraint relationship, we can say that the velocities increasing the length of the string (u)= velocities decreasing the length of string.( Component of v on any one of left or right string= v cosθ)
Therefore, v cosθ= u and hence v= u/cosθ
My approach:: I did just the reverse of this. I took components of u along the y-axis to get the speed of mass m. Here is the reason why:
The velocity of the mass M should be the vector-summation of the velocities of the string attached to block A and the string attached to block B.After all, these strings are the cause behind the motion of the mass M and thus, their "influence" must be added in order to obtain the behavior of mass M. As the motion of mass m is vertically upwards, their components must cancel along the X-axis and should add up on the Y-axis. Component of left string on Y-axis= u cosθ and component on Y-axis=u cosθ. So net resultant and the speed of mass m=2u cosθ.
Where am I wrong as the answer is not 2u cosθ?