If an object falls and hit the ground with a force, the ground also pushes it back because of third law of motion but from where does the force coming in the ground particles and they are also pushed downwards at the same time due to force of object. So what actually applies force to the fallen object?
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2 Answers
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Your object consists of atoms composed of charges (electrons and protons). Likewise, the ground is as well. As the object hits the ground, the atoms in the ground are displaced and pushed closer together. The electrons in the atoms begin to repel each other and therefore resist this compression and as a consequence your object is then pushed by the atoms in the opposite direction.
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We know of four different types of forces: strong nuclear forces, electromagnetic forces, weak nuclear forces, and gravitational forces. I believe the force from the ground on the object is electrical repulsion from the electrons in the atoms of the ground and the object being pushed closer together during the collision. A theoretical physicist can probably elaborate.
answered Nov 15, 2020 at 3:34
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$\begingroup$ Not electron it is proton repulsion or nucleus nucleus repulsion $\endgroup$ Commented Nov 15, 2020 at 4:16
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$\begingroup$ The atomic scale (where electrons interact) is where the repulsion occurs, not the nuclear scale. The atomic scale is about $10^-10$ m, the nuclear scale is about $10^-14$ m. For collisions of the type here the nucleus is not involved $\endgroup$ Commented Nov 15, 2020 at 4:29
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$\begingroup$ electrons are distributed over the wholeatom $\endgroup$ Commented Nov 15, 2020 at 4:31
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$\begingroup$ so it shouldn't be possible for them to create a good repulsion. Do you have any other argument.? $\endgroup$ Commented Nov 15, 2020 at 4:32